获取列表中每个可用项的排列

from itertools import permutations

def get_permutations(lst):
    all_permutations = []
    for r in range(1, len(lst) + 1):
        perms = permutations(lst, r)
        all_permutations.extend(perms)
    return all_permutations

# 示例列表
lst = [1, 2, 3]
permutations = get_permutations(lst)
for perm in permutations:
    print(perm)

from itertools import permutations

def get_permutations_generator(lst):
    for r in range(1, len(lst) + 1):
        for perm in permutations(lst, r):
            yield perm

# 示例列表
lst = [1, 2, 3]
permutations_gen = get_permutations_generator(lst)
for perm in permutations_gen:
    print(perm)