获取包含属性的XML树中所有节点的xpath - Python

from lxml import etree

def get_xpath_with_attributes(xml_string):
    # 解析XML文档
    root = etree.fromstring(xml_string)

    # 获取所有节点
    nodes = root.xpath("//*")

    # 遍历所有节点，获取包含属性的节点的XPath
    xpath_list = []
    for node in nodes:
        if len(node.attrib) > 0:
            xpath = root.getpath(node)
            xpath_list.append(xpath)

    return xpath_list

# 示例XML文档
xml_string = '''
<root>
    <node1 attribute1="value1">Text1</node1>
    <node2 attribute2="value2">Text2</node2>
    <node3>Text3</node3>
</root>
'''

# 调用函数获取包含属性的节点的XPath列表
xpath_list = get_xpath_with_attributes(xml_string)

# 打印结果
for xpath in xpath_list:
    print(xpath)

/root/node1
/root/node2