获取文件名并将其放入值中

<input type="file" id="fileInput" onchange="getFileName()">

<script>
function getFileName() {
  var fileInput = document.getElementById("fileInput");
  var fileName = fileInput.files[0].name;
  console.log(fileName);
  // 将文件名放入值中，可以根据具体需求进行处理
}
</script>

from flask import request

@app.route('/upload', methods=['POST'])
def upload():
    file = request.files['file']
    filename = file.filename
    print(filename)
    # 将文件名放入值中，可以根据具体需求进行处理
    return 'File uploaded successfully'

import org.springframework.web.multipart.MultipartFile;

@RequestMapping(value = "/upload", method = RequestMethod.POST)
public String upload(@RequestParam("file") MultipartFile file) {
    String filename = file.getOriginalFilename();
    System.out.println(filename);
    // 将文件名放入值中，可以根据具体需求进行处理
    return "File uploaded successfully";
}