计算一个numpy数组中具有2个或更多相邻节点的单元格的数量

import numpy as np

array = np.array([[0, 1, 0, 1],
                  [1, 0, 1, 0],
                  [0, 1, 0, 1],
                  [1, 0, 1, 0]])

count = 0
for i in range(1, array.shape[0]-1):
    for j in range(1, array.shape[1]-1):
        if (array[i, j] == 1 and
            (array[i-1, j] == 1 or
             array[i+1, j] == 1 or
             array[i, j-1] == 1 or
             array[i, j+1] == 1)):
            count += 1

print("具有2个或更多相邻节点的单元格数量为:", count)