通过保留最多重复项来子集字典列表

def findMaxSubset(dictionary):
    # 统计每个字符串中每个字符的出现次数
    charCount = [{} for _ in range(len(dictionary))]
    for i in range(len(dictionary)):
        for char in dictionary[i]:
            charCount[i][char] = charCount[i].get(char, 0) + 1
    
    # 动态规划计算具有最多重复项的子集
    dp = [[0] * (len(dictionary) + 1) for _ in range(len(dictionary) + 1)]
    for i in range(1, len(dictionary) + 1):
        for j in range(1, i + 1):
            if charCount[i-1] == charCount[i-j]:
                dp[i][j] = max(dp[i-1][j], dp[i-1][j-1] + 1)
            else:
                dp[i][j] = dp[i-1][j]
    
    # 找到具有最多重复项的子集的大小
    maxSubsetSize = max(dp[-1])
    
    # 从字典列表中选择相应数量的字符串，构成具有最多重复项的子集
    maxSubset = []
    for i in range(len(dictionary), 0, -1):
        if dp[i][maxSubsetSize] == dp[i-1][maxSubsetSize-1] + 1:
            maxSubset.append(dictionary[i-1])
            maxSubsetSize -= 1
    
    return maxSubset

# 示例用法
dictionary = ["abc", "ab", "bc", "a", "b", "c"]
maxSubset = findMaxSubset(dictionary)
print(maxSubset)