静态成员函数的模板特化; 如何？

#include<iostream>

template<typename T>
class MyClass {
public:
    static void printType() {
        std::cout << "Generic type"<< std::endl;
    }
};

template<>
void MyClass<int>::printType() {
    std::cout << "Specialized for int"<< std::endl;
}

int main() {
    MyClass<int>::printType();
    MyClass<double>::printType();
    return 0;
}