(ASP.NET)操作方法:在GridView中单击按钮以打开包含另一个网格视图的弹出窗口

<asp:GridView ID="GridView1" runat="server">
    <Columns>
        <asp:TemplateField>
            <ItemTemplate>
                <asp:Button ID="btnOpenPopup" runat="server" Text="打开弹出窗口" OnClick="btnOpenPopup_Click" />
            </ItemTemplate>
        </asp:TemplateField>
        <!-- 其他列 -->
    </Columns>
</asp:GridView>

protected void btnOpenPopup_Click(object sender, EventArgs e)
{
    // 获取按钮所在行的数据
    Button btn = (Button)sender;
    GridViewRow row = (GridViewRow)btn.NamingContainer;
    string data = GridView1.DataKeys[row.RowIndex].Value.ToString();

    // 使用JavaScript打开弹出窗口
    string script = string.Format("window.open('Popup.aspx?data={0}', 'popup', 'width=500,height=500');", data);
    ClientScript.RegisterStartupScript(this.GetType(), "openPopup", script, true);
}

<asp:GridView ID="GridView2" runat="server">
    <!-- 网格视图的列和数据绑定 -->
</asp:GridView>