C#如何在字符串中找到多余的)或(括号，并将其替换为@

using System;
using System.Text.RegularExpressions;

class Program
{
    static void Main()
    {
        string input = "This is a (sample) string with )multiple) extra (parentheses";
        
        // 使用正则表达式查找多余的括号
        string pattern = @"\((?>[^()]+|\((?<depth>)|\)(?<-depth>))*(?(depth)(?!))\)|\)(?>[^()]+|\((?<depth>)|\)(?<-depth>))*(?(depth)(?!))";
        Regex regex = new Regex(pattern);

        // 将多余的括号替换为@
        string output = regex.Replace(input, "@");

        Console.WriteLine("原始字符串：");
        Console.WriteLine(input);
        Console.WriteLine("替换后的字符串：");
        Console.WriteLine(output);
    }
}

原始字符串：
This is a (sample) string with )multiple) extra (parentheses
替换后的字符串：
This is a (sample) string with @multiple@ extra (parentheses