C将多个字符串和数字作为参数列表传递

#include <stdio.h>
#include <stdarg.h>

void printArgs(int count, ...)
{
    va_list args;
    va_start(args, count);

    for (int i = 0; i < count; i++) {
        if (i % 2 == 0) {
            char* str = va_arg(args, char*);
            printf("String: %s\n", str);
        } else {
            int num = va_arg(args, int);
            printf("Number: %d\n", num);
        }
    }

    va_end(args);
}

int main()
{
    printArgs(5, "Hello", 123, "World", 456, "C Programming");
    return 0;
}

String: Hello
Number: 123
String: World
Number: 456
String: C Programming

#include <stdio.h>

int main(int argc, char* argv[])
{
    for (int i = 1; i < argc; i++) {
        if (i % 2 == 1) {
            printf("String: %s\n", argv[i]);
        } else {
            int num = atoi(argv[i]);
            printf("Number: %d\n", num);
        }
    }

    return 0;
}

String: Hello
Number: 123
String: World
Number: 456
String: C
String: Programming