开发者社区

文档建议反馈控制台

最新优惠活动

文章/答案/技术大牛

发布

Convert date to months and year

将日期转换为月份和年份是一个常见的任务，可以使用编程语言中的日期和时间处理库来实现。以下是一个使用Python语言的示例：

from datetime import datetime

def convert_date_to_month_year(date_str):
    date_obj = datetime.strptime(date_str, '%Y-%m-%d')
    month = date_obj.strftime('%m')
    year = date_obj.strftime('%Y')
    return month, year

date_str = '2022-05-15'
month, year = convert_date_to_month_year(date_str)
print(f'Month: {month}, Year: {year}')

在这个示例中，我们首先从datetime模块中导入了datetime类。然后，我们定义了一个名为convert_date_to_month_year的函数，该函数接受一个日期字符串作为输入，并将其转换为一个datetime对象。接下来，我们使用strftime方法将日期对象转换为月份和年份，并将它们作为元组返回。

在主程序中，我们定义了一个日期字符串，并将其传递给convert_date_to_month_year函数。然后，我们打印出结果。

这个示例可以轻松地扩展到其他编程语言，只需使用相应的日期和时间处理库即可。

相关搜索:django Queryset with year(date)='2010'js date year Pyspark遍历year、month和date文件夹和子文件夹以获取最新文件 Sequelize $gt date convert to = date而非> date Spark dataset to_date/year函数 str_to_date change year data MySQL ‘'date’未定义javascript react -convert js to react 从utc格式的字符串python中提取Date-Month_year 使用CriteriaBuilder for Sql server实现的Convert(DATE，expr)使用pandas中的date和year将特定列中的date和year分隔为另一列

相关搜索:

页面内容是否对你有帮助？

有帮助

没帮助

相关·内容

matinal：ABAP中常用的日期处理函数

CALL FUNCTION 'CONVERT_DATE_TO_INTERNAL' EXPORTING date_external = '2016.01.01' "...CALL FUNCTION 'CONVERT_DATE_TO_EXTERNAL' EXPORTING date_internal = '20160101' "当前日期格式...= YEAR_OF_VALID_FROM * YEAR_OF_VALID_TO = YEAR_OF_VALID_TO * RETURNCODE...CALL FUNCTION 'CIF_GEN4_CONVERT_DATETIME' EXPORTING iv_date = sy-datum...*或者使用下面语句： CONVERT DATE sy-datum TIME sy-uzeit INTO TIME STAMP lv_timestamp TIME ZONE sy-zonlo.

2252 0

Cant convert the date-like value to string because it isnt known if its a date (no time part), ti

Log4jLoggerFactory.java:59) -- Error executing FreeMarker template FreeMarker template error: Can't convert...the date-like value to string because it isn't known if it's a date (no time part), time or date-time...date, ?time, or ?...java.lang.Thread.run(Thread.java:748) Caused by: freemarker.core.UnknownDateTypeFormattingUnsupportedException: Can't convert...the date-like value to string because it isn't known if it's a date (no time part), time or date-time

9783 0

matinal：ABAP 时间函数总结大全

ENDIF. ---- 转换日期为内部数字格式 CALL FUNCTION 'CONVERT_DATE_TO_INTERNAL' EXPORTING date_external...= 2. ---- 转换日期为系统日期格式 CALL FUNCTION 'CONVERT_DATE_TO_EXTERNAL' EXPORTING date_internal...TYPE scal-year, year_of_valid_to TYPE scal-year, return_code TYPE sy-subrc....CONVERT DATE i_date TIME i_time INTO TIME STAMP o_tstamp TIME ZONE i_tzone. CASE sy-subrc....CONVERT TIME STAMP i_tstamp TIME ZONE w_tzone INTO DATE o_date TIME o_time. CASE sy-subrc.

2451 0

Mysql数据库数据类型 year，time，date，datetime，timestamp 的区别

Mysql数据库数据类型 year，time，date，datetime，timestamp 的区别...强烈推介IDEA2020.2破解激活，IntelliJ IDEA 注册码，2020.2 IDEA 激活码 1.五种类型所表示的日期格式（为了显而易见，字段名即类型名） year 年 date 年-月-

1.4K4 0

sql分别用日期、月、年分组 group by 分组，datepart函数，datediff函数统计

=> 12 –DATEPART(year,CreateDate) => 2013 --2020-09-29 08:58:18 select convert(varchar...int set @months=DATEDIFF(month,@begin,@end) select convert(varchar(7),DATEADD(month,number,@begin) ,...days = DATEDIFF(DAY, @DATE_START, @DATE_END); SELECT convert(char(10), DATEADD(dd, number, @DATE_START...@DATE_END); SELECT @sql2 = ISNULL(@sql2 + ',', '') + '['+convert(varchar(100), duty_date, 112)+']'...FROM ( SELECT convert(varchar(10), DATEADD(dd, number, @DATE_START),112) AS duty_date FROM master.dbo.spt_values

2.5K5 0

39个 Python Datetime 小例子，拯救因时间抓狂的你

a string european_date = "31-12-2022" # European format european_format = "%d-%m-%Y" # Convert the...in range(2022, 2026): print(f"Weekday of December 31, {year} is {date(year, 12, 31).strftime(weekday_format...between two dates date_diff = second_date - first_date # Function to convert datetime to string def...print(f"Time left to New Year 2023 in NYC is: {countdown.months} months, {countdown.days} days, {countdown.hours...Time left to New Year 2023 in NYC is: 10 months, 17 days, 18 hours, 26 minutes, 16 seconds.

3.3K2 0

机器学习项目：建立一个酒店推荐引擎

列： df['date_time_year']= pd.Series(df.date_time, index= df.index) df['date_time_month']= pd.Series(df.date_time..., index= df.index) from datetimeimport datetime df.date_time_year= df.date_time_year.apply(lambda x:...get_year(x)) df.date_time_month= df.date_time_month.apply(lambda x: get_month(x)) del df['date_time']...(df.srch_ci, index=df.index) # convert year & months to int df.srch_ci_year= df.srch_ci_year.apply(lambda...']= pd.Series(df.srch_co, index=df.index) # convert year & months to int df.srch_co_year= df.srch_co_year.apply

8622 0

.NET 纯原生实现 Cron 定时任务执行，未依赖第三方组件

; private SortedSet months = null!...= new SortedSet(); months ??...">The date....hourToSet = 0; } DateTimeOffset d = new DateTimeOffset(date.Year..., date.Month, date.Day, hourToSet, date.Minute, date.Second, date.Millisecond, date.Offset);

1.1K2 0

MySQL函数大全及用法示例(三)

(date) 返回date的年份(范围在1000到9999) mysql> select year('98-02-03'); 　　-> 1998 hour(time)...: 　second 秒 seconds 　minute 分钟 minutes 　hour 时间 hours 　day 天 days 　month 月 months...天和小时 "days hours" 　year_month 年和月 "years-months" 　hour_second 小时, 分钟， "hours:minutes:seconds...month、year_month或year,天数大于结果月份的最大天数则使用最大天数) mysql> select "1997-12-31 23:59:59" + interval 1 second...：用法：convert(字段,数据类型) 实例：select convert(a ,unsigned) as b from cardserver where order by b desc;

8412 0

解决：Failed to convert value of type ‘java.lang.String‘ to required type ‘java.util.Date‘；

关注微信公众号“假装正经的程序员”，回复“日期转换”即可获取解决方案发生这一错误的主要原因是Controller类中需要接收的是Date类型，但是在页面端传过来的是String类型，最终导致了这个错误...public class UserController{ @RequestMapping(value="/login.do") public String login(String username,Date...DateFormat dateFormat=new SimpleDateFormat("yyyy-MM-dd HH:mm:ss"); binder.registerCustomEditor(Date.class...WebBindingInitializer import java.text.DateFormat; import java.text.SimpleDateFormat; import java.util.Date...DateFormat dateFormat=new SimpleDateFormat("yyyy-MM-dd HH:mm:ss"); binder.registerCustomEditor(Date.class

5.9K2 0

python获取指定日期范围内的每一天，每个月，每季度

"%Y%m") date_list.append(date_str) begin_date = add_months(begin_date,1) return date_list...def add_months(dt,months): month = dt.month - 1 + months year = dt.year + month / 12 month...= add_months(begin_date,1) return date_list def add_months(dt,months): month = dt.month -...1 + months year = dt.year + month / 12 month = month % 12 + 1 day = min(dt.day, calendar.monthrange...(year, month)[1]) return dt.replace(year=year, month=month, day=day) def getBetweenQuarter(begin_date

1.6K1 0

Python日期时间前后推移

月份推移def month_delta(months): month = sourcedate.month + months if month % 12 == 0: if month...// 12 == 1: year = sourcedate.year else: year = sourcedate.year + floor...(months / 12) month = 12 else: year = sourcedate.year + floor(months / 12) month...年份推移def year_delta(years): year = sourcedate.year +years return datetime.datetime(year, month=sourcedate.month...(years=years) if months: dst_date = dst_date + relativedelta(months=months) if days:

2391 0

Q1：如何用 C# 计算相对时间？

to the current date and generates a friendly English /// comparison ("5 days ago", "5 days from now...") /// /// The date to convert /// When off, calculate timespan down to the second. /// When on, approximate...FluentDateTime ，比如下面这些例子： var dateTime1 = 2.Hours().Ago(); var dateTime2 = 3.Days().Ago(); var dateTime3 = 1.Months...x.TotalDays:F0} days"}, { 86400, x => "about a month"}, { 525600, x => $"{x.TotalDays / 30:F0} months..."}, { 1051200, x => "about a year"}, { double.MaxValue, x => $"{x.TotalDays / 365:F0} years"}

4122 0

又肝了3天，整理了80个Python DateTime 例子，必须收藏！

print(strftime("%D", gmtime())) print(strftime("%B", gmtime())) print(strftime("%y", gmtime())) # Convert...12:00:00', '%Y-%m-%d %H:%M:%S') r = relativedelta.relativedelta(date2, date1) print(r.months + (12...= date + relativedelta(months=+6) print(date) Output: 2021-05-15 13:48:52.135612 2021-11-15 13:48:52.135612..., timedelta year = 2018 date_object = date(year, 1, 1) date_object += timedelta(days=1-date_object.isoweekday...()) while date_object.year == year: print(date_object) date_object += timedelta(days=7) Output

8.6K3 0

python开发_calendar

= [datetime.date(2001, i+1, 1).strftime for i in range(12)] 50 _months.insert(0, lambda x: "")...(year, month): 178 if date.month !...(date.day, date.weekday()) 182 183 def itermonthdays(self, year, month): 184 """ 185...in self.itermonthdates(year, month): 189 if date.month !...Days are datetime.date objects. 226 """ 227 months = [ 228 self.monthdatescalendar

6872 1

纯前端绘制精美时间轴-Timesheet.js

) { if (date.indexOf('/') === -1) { date = new Date(parseInt(date, 10), 0, 1);...date.hasMonth = false; } else { date = date.split('/'); date = new Date(parseInt...(date[1], 10), parseInt(date[0], 10) - 1, 1); date.hasMonth = true; } return date...(); } else if (beg.getFullYear() > this.year.max) { this.year.max = beg.getFullYear...fullYears - 1 : 0); } else { months += this.end.getMonth() + 1; months +=

4.8K3 0

解决：Failed to convert value of type java.lang.String to required type java.util.Date;的方法...

解决：Failed to convert value of type 'java.lang.String' to required type 'java.util.Date'; 发生这一错误的主要原因是...Controller类中需要接收的是Date类型，但是在页面端传过来的是String类型，最终导致了这个错误。...class UserController{ @RequestMapping(value="/login.do") public String login(String username,Date...DateFormat dateFormat=new SimpleDateFormat("yyyy-MM-dd HH:mm:ss"); binder.registerCustomEditor(Date.class...WebBindingInitializer import java.text.DateFormat; import java.text.SimpleDateFormat; import java.util.Date

1.8K2 0

如何使用 React 构建自定义日期选择器(1)

from 28 - 31 export const getMonthDays = (month = THIS_MONTH, year = THIS_YEAR) => { const months30...29 : 28 : months30.includes(month) ?...export const getMonthFirstDay = (month = THIS_MONTH, year = THIS_YEAR) => { return +(new Date(`${year...are of the same month and year export const isSameMonth = (date, basedate = new Date()) => { if (...as YYYY-MM-DD // Months and Days are zero padded export const getDateISO = (date = new Date) => {

6.2K1 0

hive时间函数详解

日期转年函数: year 语法: year(string date) 返回值: int 说明: 返回日期中的年。...举例： hive> select year('2011-12-08 10:03:01'); 2011 hive> select year('2012-12-08'); 2012 7. month...举例： hive> select date_sub('2021-10-08',10); 2012-11-28 17. add_months() 日期减少函数: add_months 语法: add_months...举例： select add_months(current_date,-1); +-------------+--+ | _c0 | +-------------+--+ | 2018...+-------------+--+ | 2018-09-10 | +-------------+--+ 18. months_betwween 月份比较函数: months_betwween 语法

3.5K3 0

在Django中自定义filter并在template中的使用详解

__init__(*args, **kwargs) now = timezone.now() # When time zone support is enabled, convert "now" to...(year=filter_end_date.year-1, month=12) else: filter_start_date_for_one_month = filter_end_date.replace...= filter_end_date.replace(year=filter_end_date.year-1, month=filter_start_date_for_six_month_month)...) else: filter_start_date_for_six_month = filter_end_date.replace(year=filter_end_date.year-1, month=...), self.lookup_kwarg_until: str(filter_end_date), }), ('Past 6 months', { self.lookup_kwarg_since: str

2.5K4 0

点击加载更多

扫码

添加站长进交流群

领取专属 10元无门槛券

手把手带您无忧上云

扫码加入开发者社群

相关资讯

热门标签

活动推荐

运营活动

活动名称

广告关闭