Django 1.8如何根据当前通用详细信息视图的id过滤对象

from django.views.generic import DetailView
from your_app.models import YourModel

class YourDetailView(DetailView):
    model = YourModel
    template_name = 'your_template.html'

from django.urls import path
from your_app.views import YourDetailView

urlpatterns = [
    path('your_model/<int:pk>/', YourDetailView.as_view(), name='your_detail_view'),
]

<h1>{{ object.name }}</h1>
<p>{{ object.description }}</p>

from django.views.generic import DetailView
from your_app.models import YourModel

class YourDetailView(DetailView):
    model = YourModel
    template_name = 'your_template.html'

    def get_queryset(self):
        queryset = super().get_queryset()
        queryset = queryset.filter(id=self.kwargs['pk'])
        return queryset