JPA CriteriaBuilder -如何将具有不同动态类型的参数添加到条件中？获取不明确的调用错误

import javax.persistence.criteria.CriteriaBuilder;
import javax.persistence.criteria.CriteriaQuery;
import javax.persistence.criteria.Predicate;
import javax.persistence.criteria.Root;
import javax.persistence.EntityManager;
import javax.persistence.TypedQuery;

// 获取EntityManager实例
EntityManager entityManager = ...

// 创建CriteriaBuilder对象
CriteriaBuilder criteriaBuilder = entityManager.getCriteriaBuilder();

// 创建CriteriaQuery对象
CriteriaQuery<Entity> criteriaQuery = criteriaBuilder.createQuery(Entity.class);

// 定义根实体和查询条件
Root<Entity> root = criteriaQuery.from(Entity.class);
Predicate predicate = criteriaBuilder.conjunction();

// 添加不同动态类型的参数条件
Object param1 = ...; // 第一个参数
if (param1 != null) {
    predicate = criteriaBuilder.and(predicate, criteriaBuilder.equal(root.get("property1"), param1));
}

String param2 = ...; // 第二个参数
if (param2 != null && !param2.isEmpty()) {
    predicate = criteriaBuilder.and(predicate, criteriaBuilder.like(root.get("property2"), "%" + param2 + "%"));
}

Integer param3 = ...; // 第三个参数
if (param3 != null) {
    predicate = criteriaBuilder.and(predicate, criteriaBuilder.greaterThan(root.get("property3"), param3));
}

// 将条件添加到查询中
criteriaQuery.where(predicate);

// 创建TypedQuery对象并执行查询
TypedQuery<Entity> typedQuery = entityManager.createQuery(criteriaQuery);
List<Entity> results = typedQuery.getResultList();