Java 8:如何在不将流转换回列表并获取第0个位置的值的情况下获取列表内对象中的特定值？

import java.util.Arrays;
import java.util.List;
import java.util.Optional;

public class Main {
    public static void main(String[] args) {
        List<Person> personList = Arrays.asList(
                new Person("Alice", 25),
                new Person("Bob", 30),
                new Person("Charlie", 35)
        );

        Optional<String> nameOptional = personList.stream()
                .filter(person -> person.getAge() > 30)
                .map(Person::getName)
                .findFirst();

        if (nameOptional.isPresent()) {
            String name = nameOptional.get();
            System.out.println("Name: " + name);
        } else {
            System.out.println("No matching person found.");
        }
    }
}

class Person {
    private String name;
    private int age;

    public Person(String name, int age) {
        this.name = name;
        this.age = age;
    }

    public String getName() {
        return name;
    }

    public int getAge() {
        return age;
    }
}