Java中某个时间戳后面的行的Grep log4j

import java.io.BufferedReader;
import java.io.FileReader;
import java.io.IOException;
import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.Date;

public class LogFilter {
    public static void main(String[] args) {
        String logFilePath = "path/to/log/file.log";
        String targetTimestamp = "2022-01-01 00:00:00";

        try (BufferedReader reader = new BufferedReader(new FileReader(logFilePath))) {
            String line;
            SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
            Date targetDate = dateFormat.parse(targetTimestamp);

            while ((line = reader.readLine()) != null) {
                // Assuming the timestamp is at the beginning of each log line
                String timestampStr = line.substring(0, 19);
                Date logDate = dateFormat.parse(timestampStr);

                if (logDate.after(targetDate)) {
                    System.out.println(line);
                }
            }
        } catch (IOException | ParseException e) {
            e.printStackTrace();
        }
    }
}