Javascript -遍历约会数组，查找下一个可用项

function findNextAvailableAppointment(appointments) {
  for (let i = 0; i < appointments.length; i++) {
    if (appointments[i].status === true) {
      return appointments[i];
    }
  }
  return null; // 如果没有可用的约会项，返回null或者其他合适的值
}

// 示例约会数组
const appointments = [
  { date: '2022-01-01', status: false },
  { date: '2022-01-02', status: true },
  { date: '2022-01-03', status: true },
  { date: '2022-01-04', status: false },
];

const nextAvailableAppointment = findNextAvailableAppointment(appointments);
console.log(nextAvailableAppointment); // 输出 { date: '2022-01-02', status: true }