Javascript Arrays - 检查相同内容的两个对象数组,忽略顺序

const array1 = [
  { id: 1, name: "John" },
  { id: 2, name: "Jane" },
  { id: 3, name: "Jim" }
];

const array2 = [
  { id: 2, name: "Jane" },
  { id: 1, name: "John" },
  { id: 3, name: "Jim" }
];

function arraysHaveSameContent(array1, array2) {
  if (array1.length !== array2.length) {
    return false;
  }

  const sortedArray1 = array1.sort();
  const sortedArray2 = array2.sort();

  for (let i = 0; i< sortedArray1.length; i++) {
    if (JSON.stringify(sortedArray1[i]) !== JSON.stringify(sortedArray2[i])) {
      return false;
    }
  }

  return true;
}

console.log(arraysHaveSameContent(array1, array2)); // 输出：true