Javascript，如何检查一个对象的所有属性？是否可以将其与模式进行比较？

const obj = { a: 1, b: 2, c: 3 };
const keys = Object.keys(obj);
console.log(keys); // ['a', 'b', 'c']

const obj = { a: 1, b: 2, c: 3 };
for (let key in obj) {
  console.log(key); // 'a', 'b', 'c'
}

const obj = { a: 1, b: 2, c: 3 };
const properties = Object.getOwnPropertyNames(obj);
console.log(properties); // ['a', 'b', 'c']

function compareObjectWithPattern(obj, pattern) {
  const objKeys = Object.keys(obj);
  const patternKeys = Object.keys(pattern);

  // 检查属性名称是否匹配
  if (objKeys.length !== patternKeys.length) {
    return false;
  }

  for (let key of objKeys) {
    if (!pattern.hasOwnProperty(key)) {
      return false;
    }
  }

  // 检查属性值是否匹配
  for (let key of objKeys) {
    if (obj[key] !== pattern[key]) {
      return false;
    }
  }

  return true;
}

const obj = { a: 1, b: 2, c: 3 };
const pattern = { a: 1, b: 2 };

console.log(compareObjectWithPattern(obj, pattern)); // true