NSPredicate只返回与字符串列表中第一个元素的关键字匹配的任何记录

let keywords = ["apple", "banana", "cherry"]
let predicate = NSPredicate(format: "name == %@", keywords.first!)

let keywords = ["apple", "banana", "cherry"]
let predicate = NSPredicate(format: "name IN %@", keywords)

let keywords = ["apple", "banana", "cherry"]
let subpredicates = keywords.map { NSPredicate(format: "name == %@", $0) }
let predicate = NSCompoundPredicate(orPredicateWithSubpredicates: subpredicates)

import Foundation

// 假设有一个 Fruit 类和一个 fruits 数组
class Fruit {
    var name: String
    init(name: String) {
        self.name = name
    }
}

let fruits = [
    Fruit(name: "apple"),
    Fruit(name: "banana"),
    Fruit(name: "cherry"),
    Fruit(name: "date"),
    Fruit(name: "elderberry")
]

// 关键字列表
let keywords = ["apple", "cherry"]

// 构建谓词
let predicate = NSPredicate(format: "name IN %@", keywords)

// 过滤 fruits 数组
let filteredFruits = (fruits as NSArray).filtered(using: predicate) as! [Fruit]

// 打印结果
for fruit in filteredFruits {
    print(fruit.name)
}

apple
cherry