Python:如何创建列表列表，并由两个后续数字配对

# 假设我们要创建一个包含从1到n的数字对的列表列表
n = 5
pairs = [[i, i+1] for i in range(1, n)]
print(pairs)

[[1, 2], [2, 3], [3, 4], [4, 5]]

pairs = []
for i in range(1, n):
    pairs.append([i, i+1])
print(pairs)

[[1, 2], [2, 3], [3, 4], [4, 5]]

import numpy as np

n = 5
pairs = np.column_stack((np.arange(1, n), np.arange(2, n+1)))
print(pairs.tolist())

[[1, 2], [2, 3], [3, 4], [4, 5]]

def generate_pairs(n):
    for i in range(1, n):
        yield [i, i+1]

pairs_generator = generate_pairs(1000000)