Python:如何查找1到9之间缺少的数字？

def find_missing_numbers():
    numbers = range(1, 10)
    missing_numbers = []
    for num in numbers:
        if num not in [2, 5, 7]:
            missing_numbers.append(num)
    return missing_numbers

result = find_missing_numbers()
print(result)  # 输出: [1, 3, 4, 6, 8, 9]

def find_missing_numbers():
    numbers = set(range(1, 10))
    existing_numbers = set([2, 5, 7])
    missing_numbers = numbers - existing_numbers
    return sorted(missing_numbers)

result = find_missing_numbers()
print(result)  # 输出: [1, 3, 4, 6, 8, 9]