Python:根据投影值的相等将列表分组为子列表

def group_by_projection(lst, projection_func):
    groups = {}
    for item in lst:
        projection = projection_func(item)
        if projection in groups:
            groups[projection].append(item)
        else:
            groups[projection] = [item]
    return list(groups.values())

lst = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

def projection_func(x):
    return x % 2  # 根据元素的奇偶性分组

result = group_by_projection(lst, projection_func)
print(result)

[[1, 3, 5, 7, 9], [2, 4, 6, 8, 10]]