Python统计列表中的子字符串个数，不重复的其他字符串列表中的子字符串的个数

def count_substring(substring, string_list):
    count = 0
    for string in string_list:
        count += string.count(substring)
    return count

# 测试代码
my_list = ["abc", "defabc", "abcdef", "xyz"]
sub_count = count_substring("abc", my_list)
print(sub_count)  # 输出：3

def count_unique_substrings(string_list):
    substrings = set()
    for string in string_list:
        for i in range(len(string)):
            for j in range(i+1, len(string)+1):
                substrings.add(string[i:j])
    return len(substrings)

# 测试代码
my_list = ["abc", "defabc", "abcdef", "xyz"]
unique_sub_count = count_unique_substrings(my_list)
print(unique_sub_count)  # 输出：16