Swift:解码JSON响应并将嵌套的JSON存储为字符串或JSON

import Foundation

// 假设这是你的 JSON 响应
let jsonString = """
{
    "name": "John Doe",
    "age": 30,
    "address": {
        "street": "123 Main St",
        "city": "Anytown"
    }
}
"""

// 定义一个符合 Codable 协议的结构体来映射 JSON 数据
struct Person: Codable {
    let name: String
    let age: Int
    let address: Address
    
    struct Address: Codable {
        let street: String
        let city: String
    }
}

// 将 JSON 字符串转换为 Data
if let jsonData = jsonString.data(using: .utf8) {
    do {
        // 解码 JSON 数据到 Person 结构体
        let person = try JSONDecoder().decode(Person.self, from: jsonData)
        
        // 将嵌套的 JSON 转换为字符串
        if let nestedJsonString = try? JSONEncoder().encodeToString(person.address) {
            print("Nested JSON as String: \(nestedJsonString)")
        }
        
        // 或者保持 JSON 格式存储为 Data
        if let nestedJsonData = try? JSONEncoder().encode(person.address) {
            print("Nested JSON as Data: \(nestedJsonData)")
        }
    } catch {
        print("Failed to decode JSON: \(error)")
    }
}