While循环.isdigit。为什么函数'123‘而不是'abc123’出现错误？

# 正确使用 isdigit() 方法
print('123'.isdigit())  # 输出: True
print('abc123'.isdigit())  # 输出: False

# 错误的使用方式，通常不会出现，因为 isdigit() 不会抛出错误
try:
    print('123'.isdigit())
except Exception as e:
    print(f"Error: {e}")

try:
    print('abc123'.isdigit())
except Exception as e:
    print(f"Error: {e}")

# 确保变量是字符串类型
value = '123'
if isinstance(value, str) and value.isdigit():
    print("Value is all digits.")
else:
    print("Value contains non-digit characters or is not a string.")

# 处理可能的非字符串输入
value = 123  # 假设这是一个错误的输入
try:
    if isinstance(value, str) and value.isdigit():
        print("Value is all digits.")
    else:
        print("Value contains non-digit characters or is not a string.")
except AttributeError as e:
    print(f"Error: {e}. Ensure the value is a string.")