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问题:XPath最后一次出现的每个元素
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答案:
要找到XPath最后一次出现的每个元素,可以使用以下方法:
import xml.etree.ElementTree as ET
# 解析XML文档
tree = ET.parse('document.xml')
# 获取文档中的所有节点
root = tree.getroot()
# 定义变量,用于存储XPath最后一次出现的每个元素的值
last_elements = []
# 遍历所有节点,找到XPath最后一次出现的每个元素
for element in root.findall('.//{xpath}'):
if element.attrib.get('last'):
last_elements.append(element)
# 输出XPath最后一次出现的每个元素的值
print(last_elements)
import java.io.IOException;
import javax.xml.xpath.XPath;
import javax.xml.xpath.XPathConstants;
import javax.xml.xpath.XPathExpressionException;
import javax.xml.xpath.XPathFactory;
import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.w3c.dom.NodeList;
public class XPathLastElements {
public static void main(String[] args) throws IOException, XPathExpressionException {
String xml = "<?xml version=\"1.0\" encoding=\"UTF-8\"?>\n" +
"<root>\n" +
" <element key=\"1\">\n" +
" <content>内容1</content>\n" +
" </element>\n" +
" <element key=\"2\">\n" +
" <content>内容2</content>\n" +
" </element>\n" +
" <element key=\"3\">\n" +
" <content>内容3</content>\n" +
" </element>\n" +
"</root>";
Document document = XML.toDocument(xml);
XPath xpath = XPathFactory.newInstance().newXPath();
XPathExpression expression = xpath.compile("//*[contains(@key, 'element') and not(contains(@key, 'last'))]");
NodeList nodes = (NodeList) expression.evaluate(document, XPathConstants.NODESET);
for (int i = 0; i < nodes.getLength(); i++) {
Element element = (Element) nodes.item(i);
System.out.println(element.getAttribute("key"));
}
}
}
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <libxml/HTMLparser.h>
#include <libxml/xpath.h>
// 解析XML文档
void parse_xml(const char xml_str, xmlNode root) {
xmlDocPtr doc = xmlReadMemory(xml_str, strlen(xml_str), NULL, NULL, 0);
if (doc == NULL) {
fprintf(stderr, "Error parsing XML: %s\n", strerror(XML_ERROR_NO_MEMORY));
return;
}
xmlXPathContextPtr context = xmlXPathNewContext(doc);
if (context == NULL) {
fprintf(stderr, "Error creating XPath context\n");
xmlFreeDoc(doc);
return;
}
// 定义XPath表达式
xmlChar* xpath = xmlCharStrdup(BAD_CAST "//*[contains(@key, 'element') and not(contains(@key, 'last'))]");
if (xpath == NULL) {
fprintf(stderr, "Error allocating XPath expression: %s\n", strerror(XML_ERROR_NO_MEMORY));
xmlXPathFreeContext(context);
xmlFreeDoc(doc);
return;
}
// 执行XPath表达式,查找符合条件的节点
xmlNode* node = xmlXPathEvalExpression(context, xpath, NULL, NULL);
if (node == NULL) {
fprintf
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