Xamarin.Forms如何将代码中的数据绑定到卷帘视图(在xaml中工作)

<ContentPage xmlns="http://xamarin.com/schemas/2014/forms"
             xmlns:x="http://schemas.microsoft.com/winfx/2009/xaml"
             xmlns:local="clr-namespace:MyApp"
             x:Class="MyApp.MainPage"
             x:Name="page">
    <StackLayout>
        <Label Text="{Binding Name}" />
        <Button Text="Toggle" Clicked="Toggle_Clicked" />
        <Grid>
            <Grid.RowDefinitions>
                <RowDefinition Height="*" />
                <RowDefinition Height="Auto" />
            </Grid.RowDefinitions>
            <Label Grid.Row="0" Text="{Binding Description}" />
            <ScrollView Grid.Row="1" x:Name="scrollView">
                <ListView ItemsSource="{Binding Items}">
                    <ListView.ItemTemplate>
                        <DataTemplate>
                            <TextCell Text="{Binding .}" />
                        </DataTemplate>
                    </ListView.ItemTemplate>
                </ListView>
            </ScrollView>
        </Grid>
    </StackLayout>
</ContentPage>

namespace MyApp
{
    public partial class MainPage : ContentPage
    {
        private bool isToggled;
        
        public MainPage()
        {
            InitializeComponent();
            
            // 设置数据上下文
            page.BindingContext = new ViewModel();
        }
        
        private void Toggle_Clicked(object sender, EventArgs e)
        {
            isToggled = !isToggled;
            
            // 更新数据模型中的属性值
            ((ViewModel)page.BindingContext).Name = isToggled ? "Toggled" : "Not Toggled";
            ((ViewModel)page.BindingContext).Description = isToggled ? "This is the toggled state." : "This is not the toggled state.";
        }
    }
    
    public class ViewModel
    {
        public string Name { get; set; }
        public string Description { get; set; }
        public List<string> Items { get; set; }
        
        public ViewModel()
        {
            Name = "Not Toggled";
            Description = "This is not the toggled state.";
            Items = new List<string> { "Item 1", "Item 2", "Item 3" };
        }
    }
}