array [100] = {0}如何将整个数组设置为0？

#include<iostream>
#include<algorithm>

int main() {
    int array[100] = {0};
    std::fill(array, array + 100, 0);
    return 0;
}

using System;

class Program {
    static void Main() {
        int[] array = new int[100];
        Array.Clear(array, 0, array.Length);
    }
}

import java.util.Arrays;

public class Main {
    public static void main(String[] args) {
        int[] array = new int[100];
        Arrays.fill(array, 0);
    }
}

array = [0] * 100
array.clear()

let array = new Array(100).fill(0);

package main

import "fmt"

func main() {
    array := make([]int, 100)
    for i := range array {
        array[i] = 0
    }
    fmt.Println(array)
}

array = Array.new(100, 0)

var array = Array(repeating: 0, count: 100)

val array = Array<Int>(100) { 0 }

fn main() {
    let array = vec![0; 100];
    println!("{:?}", array);
}

$array = array_fill(0, 100, 0);

use List::Util qw(first);

my @array = (0) x 100;

array <- rep(0, 100)

array = zeros(1, 100);

WITH RECURSIVE cte(n) AS (
  SELECT 1
  UNION ALL
  SELECT n + 1 FROM cte WHERE n < 100
)
SELECT 0 FROM cte;

findall(0, between(1, 100, _), Array).

array = replicate 100 0

val array = new Array[Int](100)
Arrays.fill(array, 0)

Array = lists:duplicate(100, 0).

(def array (repeat 100 0))

local array = {}
for i = 1, 100 do
    table.insert(array, 0)
end

(define array (build-list 100 (λ (x) 0)))

(define array (make-vector 100 0))