在mySql数据库中插入来自php脚本的记录时,我遇到了一个问题。下面是我的代码:
// Set fields for post record insertion
$insertPostSql = "INSERT INTO tl_posts(title, city, city_id, video_url, thumbnail_url, description, longitude, latitude, user_id, category, hotel_id, restaurant_id, activity_id, creation_date, qualified)
VALUES(:t
当在pgadminIII中执行update语句时,它的工作精细false是更新列值
update tbl_student_colleges set target=false where id=9
当对Symfony脚本值做同样的处理时,True可以很好地工作,而在false时则不能工作。
$apptQuery = "insert into tbl_student_colleges (student_id,college_id,college_name,target,applied,accepted,attending,scholarship,created_at,created_by_
我得到了这个错误:
Warning: PDOStatement::execute() [pdostatement.execute]: SQLSTATE[HY093]: Invalid parameter number: number of bound variables does not match number of tokens in /FondManager.class.php on line 69
当尝试执行此操作时:
$Fond_Modif = $Manager->get($id);
$Fond_Modif->setContactname($_POST['name
error 1 (solved): Access to XMLHttpRequest at 'http://example.com/projects/saveBoors/' from origin
'http://www.tsetmc.com' has been blocked by CORS policy:
No 'Access-Control-Allow-Origin' header is present on the requested resource.
error 2: Failed to load resource: net::ER
我收到此错误: SQLSTATE42000:语法错误或访问冲突: 1064您的SQL语法中有一个错误;请查看与您的MySQL服务器版本对应的手册,以获取正确的语法,以便在第2行使用'INSERT INTO student_details (student_id,first_name,last_name,道布,address_lin
对于这段代码:有什么想法吗?
//create variables from each value that was submitted from the form */
$student_info_id = $_POST['student_info
我正在尝试更新表中的数据,其中包含一个位类型值,如下所示:
// $show_contact is either '1' or '0'
$query->bindValue(':scontact', $show_contact, PDO::PARAM_INT);
问题是,它从来不改变值,它仍然是'1‘设置在PHPMyAdmin上。我尝试了不同的PDO::PARAM_类型,但没有成功,其他一切都正常。
编辑完整脚本
$sql = "UPDATE users SET password = :password, ad