public class MAUtils { private void test(int dayCount) { //算法公式:MA(C,X)=(X1+X2+…+XX)/X....List dataList = new ArrayList(); for (int i = 0; i dayCount; i++) { Data...); } List maResults = new ArrayList(); for (int days = 0; days dayCount
Flow.Subscription subscription; private AtomicInteger available = new AtomicInteger(0); private int dayCount...; public MilkCustomer(int dayCount) { this.dayCount = dayCount; } @Override public void onSubscribe...(Flow.Subscription subscription) { this.subscription = subscription; //设置总量 available.set(dayCount...} @Override public void onComplete() { System.out.println("closed."); } } MilkCustomer 接受一个dayCount
但是某一天我手动触发任务的时候，传值100的时候，问题出现了 贴出我的时间计算代码： //往前推算x天 int dayCount = 10; Long...endTime = System.currentTimeMillis(); Long startTime = endTime - (dayCount * 24 * 60 * 60 *...现在我们调高到100，看看输出： //往前推算x天 int dayCount = 100; Long endTime = System.currentTimeMillis...//往前推算x天 int dayCount = 100; Long endTime = System.currentTimeMillis(); Long...startTime = endTime - (dayCount * 24 * 60 * 60 * 1000); System.out.println(new Date(endTime)
YearSelector.val()); var month = parseInt($MonthSelector.val()); var dayCount...case 8: case 10: case 12: dayCount...case 6: case 9: case 11: dayCount...30; break; case 2: dayCount...= 0) || (year % 400 == 0)) { dayCount = 29;
case 8: case 10: case 12: dayCount...case 6: case 9: case 11: dayCount...30; break; case 2: dayCount...= 0) || (year % 400 == 0)) { dayCount = 29;...var daySel = $DaySelector.attr("rel"); for (var i = 1; i dayCount
close:3.0,low:3.0,high:3.0}, {open:5.0,close:3.0,low:3.0,high:3.0} ]; /* * 计算MA */ calcMA=function(dayCount...,data,field) { var ma=[]; for (var days = 0; days dayCount; days++) { let sum = 0; for (var
nums := [][]int{{1, 2, 3}, {4, 5, 6}} days := []int{2} headCount := []int{3} ret := dayCount...(nums, days, headCount) fmt.Println(ret) } func dayCount(nums [][]int, days []int, headCount []int
GROUP_CONCAT(JSON_OBJECT('ukey',ukey,'utype',utype,'endtime',endtime,'uenable',uenable,'daymax',daymax,'daycount...',daycount)),']') as reluast from ${db_name}.ipuser where ukey='${ukey}'" | grep ']') echo "${userinfo...，请联系管理员开通" fi if [ $(echo "${userinfo}" | jq -r .[0].daymax) -lt $(echo "${userinfo}" | jq -r .[0].daycount...=$(echo "${userinfo}" | jq -r .[0].daycount) n=$(( ${daycount} + 1 )) sql "update ${db_name}.ipuser set...daycount='${n}' where ukey='${ukey}'" fi // ip 查询脚本 ip_check.sh 由 main_chec.sh 调用 #!
ads_uv_count uv where uv.dt='2019-02-10'; 需求十一：品牌复购率 需求：以月为单位统计，购买2次以上商品的用户，用户购买商品明细表 dws_sale_detail_daycount...：（宽表）建表dws_sale_detail_daycount drop table if exists dws_sale_detail_daycount; create external table...dws_sale_detail_daycount( user_id string comment '用户 id', sku_id string comment '商品 Id', user_gender...用户购买商品明细表' partitioned by(`dt` string) stored as parquet location '/warehouse/gmall/dws/dws_sale_detail_daycount...2019-02-10' and user_id is not null group by user_id, sku_id ) insert overwrite table dws_sale_detail_daycount
Flow.Subscription subscription; private AtomicInteger available = new AtomicInteger(0); private int dayCount...; public MilkCustomer(int dayCount) { this.dayCount = dayCount; } @Override...Flow.Subscription subscription) { this.subscription = subscription; //设置总量 available.set(dayCount...Override public void onComplete() { System.out.println("closed."); } } MilkCustomer 接受一个dayCount
11 int dayCount = 1; 12 D:经过多少天，小芳才可以存到100元钱。...13 double result = 100; 14 E:这一天是存钱的第5天或者5的倍数的话，她都会花去6元钱， 15 说明要判断dayCount...16 daySum -= 6; 17 由此还隐含了一个问题，就是要判断dayCount的值，如果不是5的倍数天的话，钱要累加。...41 if(daySum >= result) { 42 System.out.println("共花了"+dayCount+"天存储了100元"...); 43 break; 44 } 45 46 if(dayCount%5 == 0)
annualRate = 0.05 #名义报价的年化利率 dayCount = ql.ActualActual() #按照calendar day 计算计息日 compoundType = ql.Compounded...#复利计算 frequency = ql.Annual #每年付息一次 interestRate = ql.InterestRate(annualRate, dayCount, compoundType
).getTime() + ""; return timestamp; }, /** * 获取当前日期前后几天当天的日期的方法 (年月日) * @dayCount...* getYMDStr(0):当天 、 getYMDStr(1):后一天、getYMDStr(-1):前一天 * */ getYMDStr: function (dayCount...) { var dd = new Date(); dd.setDate(dd.getDate() + dayCount);//获取dayCount天后的日期
select '2019-02-10' dt, count(*) ct from dws_uv_detail_day where dt='2019-02-10' )daycount...count (*) ct from dws_uv_detail_mn where mn=date_format('2019-02-10','yyyy-MM') )mncount on daycount.dt...'$do_date' dt, count(*) ct from "$APP".dws_uv_detail_day where dt='$do_date' )daycount...date_add(next_day('$do_date','MO'),-7),'_' ,date_add(next_day('$do_date','MO'),-1) ) ) wkcount on daycount.dt...(*) ct from "$APP".dws_uv_detail_mn where mn=date_format('$do_date','yyyy-MM') )mncount on daycount.dt
count (*) ct from dws_uv_detail_mn where mn=date_format('2019-02-10','yyyy-MM') )mncount on daycount.dt...'$do_date' dt, count(*) ct from "$APP".dws_uv_detail_day where dt='$do_date' )daycount...date_add(next_day('$do_date','MO'),-7),'_' ,date_add(next_day('$do_date','MO'),-1) ) ) wkcount on daycount.dt...：（宽表）建表dws_sale_detail_daycount drop table if exists dws_sale_detail_daycount; create external table...dws_sale_detail_daycount( user_id string comment '用户 id', sku_id string comment '商品 Id', user_gender
{ month.clear(); nowDate = new Date(date.getTime());//这里做一个备份，以备下次比较使用 int dayCount...= getItemDayCount(date);//获取当月总共几天 int itemCount = (dayCount % 7 == 0) ?...(dayCount / 7) : (dayCount / 7) + 1; date.setDate(1);//设置日历时间，到当月1号。
Date& operator--(); // 后置 Date operator--(int); //日期-日期 int operator-(const Date& d); //int DayCount..._month = 12; } return day; } //日期-日期 int Date::operator-(Date& d) { int day = d.DayCount(); int...Day = DayCount();//实际上是this->DayCount() , this省略了 return Day - day; } 从这里看出，我们上面的函数是没问题的。...(); // int Day = DayCount();//实际上是this->DayCount() , this省略了 // // return Day - day; //} int Date::...()<<endl; Date d; cout DayCount()<<endl;*/ Date d5(2022, 9, 8); cout << d5 - d1 << endl;
分析： A:小芳的妈妈每天给她2.5元钱 double dayMoney = 2.5; B:她都会存起来 double daySum = 0; C:从第一天开始存储 int dayCount...double result = 100; E:这一天是存钱的第5天或者5的倍数的话，她都会花去6元钱， 说明要判断dayCount的值，如果对5整除就减去6元钱。...] args) { //每天要存储的钱是2.5元 double dayMoney = 2.5; //存钱的初始化值是0 double daySum = 0; //从第一天开始存储 int dayCount...if(daySum >= result) { System.out.println("共花了"+dayCount+"天存储了100元"); break; } if(dayCount%5 == 0...) { //花去6元钱 daySum -= 6; System.out.println("第"+dayCount+"天花了6元钱"); } //天数变化 dayCount++; } }
) { double daymony = 2.5; double summoney = 0; int result =100; int daycount...summoney+=daymony; if(summoney>=result){ break; } if(daycount...%5==0){ summoney-=6; } daycount++; } System.out.println...(daycount); } } 方法(method):是完成特定功能的代码块 在Java中，方法是一段封装了特定功能的可执行代码块。
)) # 获取月份 d = int(input('请输入是哪一天：')) # 获取“日” targetDay = datetime.date(y, m, d) # 将输入的日期格式化成标准的日期 dayCount...% (targetDay, y, dayCount.days)) ``` 方法三 import datetime dtime = input("请输入求天数的日期(20191111)：") tnum
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