# Use the file name mbox-short.txt as the file name
fname = raw_input("Enter file name: ")
count = 0
avg = 0
fh = open(fname)
for line in fh:
if not line.startswith("X-DSPAM-Confidence:") :
continue
count = count + 1
pos = line.find(":")
new = flo
我得到以下缩进错误
>>> number = 35
>>> if number == 35:
print 'true'
else:
File "<pyshell#130>", line 3
else:
^
IndentationError: unindent does not match any outer indentation level
>>>
这只会在空闲时发生,而不会发生在命令行上。我在Windows XP上使用Python 2.6.4。我已经在
我找不到下面这个错误的解决方案,它不接受打印或返回:
>>> vendors = ['cisco','juniper','alcatel','huawei']
>>> for x in vendors:
... print (x)
File "<stdin>", line 2
print (x)
^
IndentationError: expected an indented block after 'for' statement
我有以下代码,当我只想让代码保持原样时,我讨厌不得不将代码缩进到同一行?
我必须将其缩进到:
.content.first
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<div
例如,我正在编辑这段代码:
<html>
<body>
<script>
var a = 10;
a += 100;
</script>
</body>
</html>
现在我需要缩进脚本行:
<html>
<body>
<script>
var a = 10;
a += 100;
</script>
</body>
</html>
如果不将光标移动到每行的开头并按Tab,我如何做到这一点
我正在尝试将CSS应用于我的html模板上的单个{{form}}字段。我引用了这个已解决的问题:
`
使用答案,我创建了我的forms.py页面,如下所示:
from django import forms
from .models import ContactInfo
class ContactForm(forms.ModelForm):
# class meta brings in the fields from models
class Meta:
model = ContactInfo
# grab the fields from models ContactIn
我试图编译这段代码:
from collections import OrderedDict
import pdb
pdb.set_trace()
def alphaDict(words):
alphas = OrderedDict()
words = sorted(words, key = str.lower)
words = filter(None, words);
for word in words:
if word[0].upper() not in alphas:
alphas[word[0].upper()]
我对VIM非常陌生,并且一直在使用bundle来格式化/着色/缩进我的文件。我最近从这里下载了一个typescript vim语法“捆绑包”:,问题是缩进对我来说似乎是坏的,考虑一下下面的例子,在自动缩进(gg=G)文件之后:
module Module {
class Foo {
// some string here
bar: string; // bar is incorrectly indented
}
}
而事实上,我期望的是:
module Module {
class Foo {
// some s
我搜索了一下,但还没有找到答案,所以我看到了一段代码如下,
int a=0, b=1, c=0;
if (a)
if (b && c) puts ("yes");
else puts ("no");
我知道如果语句只有1行类似于if (true) //something;,我们可能不会使用{},所以我假设else属于if (a),但是当我运行代码时,no没有出现,起初我认为它与
if (a) if (b && c) puts ("yes");
else puts ("no");
或,
if (a)