java Armstrong代码中的"if“条件问题

import java.util.Scanner;

public class ArmstrongNumber {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        System.out.print("请输入一个整数：");
        int number = scanner.nextInt();
        int originalNumber, remainder, result = 0, n = 0;

        originalNumber = number;

        // 计算数字的位数
        while (originalNumber != 0) {
            originalNumber /= 10;
            ++n;
        }

        originalNumber = number;

        // 按照Armstrong数的定义进行计算
        while (originalNumber != 0) {
            remainder = originalNumber % 10;
            result += Math.pow(remainder, n);
            originalNumber /= 10;
        }

        // 判断是否为Armstrong数
        if (result == number) {
            System.out.println(number + " 是一个Armstrong数");
        } else {
            System.out.println(number + " 不是一个Armstrong数");
        }
    }
}