js 提取公共方法

const users = [
  { id: 1, name: 'Alice', active: true },
  { id: 2, name: 'Bob', active: false },
  // 更多用户...
];

// 处理活跃用户
const activeUsers = users.filter(user => user.active).map(user => user.name);
console.log(activeUsers); // ['Alice']

// 另一处同样需求
const admins = [
  { id: 101, name: 'Admin1', active: true },
  { id: 102, name: 'Admin2', active: false },
  // 更多管理员...
];

const activeAdmins = admins.filter(admin => admin.active).map(admin => admin.name);
console.log(activeAdmins); // ['Admin1']

/**
 * 过滤并映射数组中的活跃项
 * @param {Array} array - 要处理的数组
 * @param {String} key - 判断活跃的键
 * @param {String} mapKey - 映射返回的键
 * @returns {Array} - 处理后的新数组
 */
function getActiveItems(array, key = 'active', mapKey = 'name') {
  return array.filter(item => item[key]).map(item => item[mapKey]);
}

const activeUsers = getActiveItems(users);
console.log(activeUsers); // ['Alice']

const activeAdmins = getActiveItems(admins);
console.log(activeAdmins); // ['Admin1']