js中json的使用方法

let jsonString = '{"name": "John", "age": 30, "city": "New York"}';
let jsonObject = JSON.parse(jsonString);
console.log(jsonObject.name); // 输出: John

let person = {
    name: "John",
    age: 30,
    city: "New York"
};
let jsonString = JSON.stringify(person);
console.log(jsonString); // 输出: {"name":"John","age":30,"city":"New York"}

try {
    let invalidJsonString = '{"name": "John", "age":}';
    let jsonObject = JSON.parse(invalidJsonString);
} catch (error) {
    console.error("解析JSON时出错:", error);
}

let objA = {};
let objB = { parent: objA };
objA.child = objB;

try {
    let jsonString = JSON.stringify(objA);
} catch (error) {
    console.error("序列化JSON时出错:", error);
}

// 定义一个JavaScript对象
let person = {
    name: "John",
    age: 30,
    city: "New York"
};

// 将对象转换为JSON字符串
let jsonString = JSON.stringify(person);
console.log("JSON字符串:", jsonString);

// 将JSON字符串转换回对象
let parsedPerson = JSON.parse(jsonString);
console.log("解析后的对象:", parsedPerson.name, parsedPerson.age, parsedPerson.city);