js前端怎么获得地址中的参数

// 假设当前URL是 https://example.com?name=John&age=30
const params = new URLSearchParams(window.location.search);

// 获取单个参数
const name = params.get('name'); // "John"
const age = params.get('age');   // "30"

console.log(name, age);

function getQueryParams() {
    const queryString = window.location.search.substring(1); // 去掉开头的问号
    const params = {};
    const pairs = queryString.split('&');

    for (const pair of pairs) {
        const [key, value] = pair.split('=');
        params[decodeURIComponent(key)] = decodeURIComponent(value || '');
    }

    return params;
}

// 假设当前URL是 https://example.com?name=John&age=30
const queryParams = getQueryParams();
console.log(queryParams.name); // "John"
console.log(queryParams.age);   // "30"

const encodedParam = encodeURIComponent('John Doe');
const decodedParam = decodeURIComponent(encodedParam);

const age = params.get('age');
const parsedAge = isNaN(age) ? 0 : parseInt(age, 10);