我有一个散列,我想要按升序对键进行数字排序,并按字母升序对其值进行排序。
#!/usr/bin/perl
use warnings;
use strict;
use List::MoreUtils;
use Tie::IxHash;
my %KEY_VALUE;
#tie %KEY_VALUE,'Tie::IxHash';
my %KEY_VALUE= (
0 => [ 'A', 'C', 'B', 'A' ,'D'],
5 => [ 'D'
我在JavaScript中有一个对象数组。我想按特定指标对它们进行排序。在一种特殊情况下会发生这种情况,即度量每次都具有相同的值。下面是一个数组示例:
var myArray = [{"key":400686,"metric":999999},{"key":52601288,"metric":999999},{"key":1380180030,"metric":999999},{"key":909661,"metric":999999},{"key":
我试图对数组中的键/val结构进行排序,它是b-树的一个树节点。当我将键/val插入到节点中时,我将其放置在结构的末尾,然后执行qsort。
struct kv
{
char *key; //This is the key
int lba; //The value of the key
unsigned char size; //Size of key for memcmp.
};
struct tnode
{
unsigned char nkeys;
unsigned char keysize;
我有一个数字字符串数组,如下所示:
vals = ['is the key resource of', 'key resource of', 'entanglement is the', 'entanglement is the key resource of', 'is the key resource', 'the key resource of', 'entanglement is the key', 'entanglement is the key resource&
在Hadoop的二级排序中,组合中的代码有以下方法来比较值,组合键类实现了WritableComparable:
@Override
public int compareTo(CustomKey o) {
int result = firstName.compareTo(o.getFirstName());
log.debug("value is " + result);
if (result == 0) {
return lastName.compareTo(o.getLastName());
以下列对象为例:
var object = {
some_key: 'some value',
some_other_key: 'some other value',
AKey: 'notice that some will have underscores and some wont.'
callBackl: 'http://google.ca'
}
应成为:
var object = {
AKey: 'notice that some will have underscores and some w
下面查询的查询结果是什么?
select * from Comment where photo_id = "xxx";
我的订单将是最近的comment_id订单吗?
或
我的订单是否按Desc从高到低的分数排序?
class Comment(Model):
photo_id = UUID(primary_key=True)
comment_id = TimeUUID(primary_key=True, default=uuid1) # second primary key component is a clustering key
我有四个全局临时表(##A,##B,##C,##D),我想在Server 2008中执行一个left join。对于全局临时表,我的意思是使用如下代码创建它们:
SELECT *
INTO ##A
这四个表都有一个名为“key”的列,我希望使用这个列来执行联接。我使用的是这样的逻辑:
SELECT *
INTO ##X
FROM ##A as a
LEFT JOIN ##B as b ON a.key = b.key
LEFT JOIN ##C as c ON a.key = c.key
LEFT JOIN ##D as d on a.key = d.key
当我执行这段代码时,我会得到以下
这是我的课
公共阶层人士{
int id;
int salary;
Map<String,List<String>> house;
//getter and setters omitted for brevity
public static void main(String[] args) {
// TODO Auto-generated method stub
Map<String,List<String>> map =new HashMap<>();
map.put("KEY_