$qs = 'SELECT cnam,COUNT(*) as cnt FROM cdr WHERE '.$where.' GROUP BY COUNT(*)';
$objRs = mysql_query($qs);
while($obj = mysql_fetch_array($objRs))
{
if ($obj['cnam'])
{
$names[$obj['cnam']]['call_name'] += $obj['cnt'];
}
}
foreach
我想得到所有记录的编号,并得到最后一张记录:
$sql_count_sms = "SELECT count(*) as total,content,id FROM android_users_sms WHERE user_id=$id ORDER BY id DESC";
$result_count_sms = mysql_query($sql_count_sms);
$row_num_sms = mysql_fetch_assoc($result_count_sms);
$num_sms = $row_num_sms['total
在MySQL WHERE子句中使用派生值不起作用。有没有办法模拟这种行为?下面是一个由于WHERE count > 5行而失败的查询示例:
SELECT
title,
company_id,
count( id ) as count
FROM
table
WHERE
count > 5
GROUP BY
title,
company_id
我正在努力更好地理解MySQL是如何工作的。我遇到了一个小组的问题。从问题中,我理解为什么这段代码会返回一个错误:
SELECT b.Title, b.Isbn
FROM Book AS b
INNER JOIN Writing AS w ON w.Book_id = b.ID
GROUP BY b.ID
HAVING w.Author_id = 1 AND b.Title LIKE "%Head%"
该错误是:“具有子句中的未知列'w.Author_id‘”,因为:
标准要求必须只引用GROUP子句中的列或聚合函数中使用的列。但是,MySQL支持对此行为的扩展,并允许
mysql> select COUNT(*), * from help_keyword;
ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '* from help_keyword' at line 1
这个不是:
mysql> select COUNT(*), help_keyword.* from help_
我正在使用下面的查询来使用left join从两个表中获取多个列的总和。但是mysql显示了“错误代码: 1111.无效使用组函数”的错误,请指出我的错误所在?
SELECT url as Domain,
A.advertiserid as advertiserid,
count(A.salesId) as Impressions,
Sum(IF(A.click1datetime IS NULL,0,1)) AS Clicks,
sum(count(B.order_id)) as Sales,
sum(sum(B.order_amount)) as SalesAmount
使用此查询时,我收到一个错误
select dbresultsid, TestCase, BuildID, Analyzed,
Verdict,
(select count(Verdict) from results where BuildID = 'Beta1'
and Verdict = 'PASS') AS PASS,
(select count(Verdict) from results where BuildID = 'Beta1'
and Ver
如何使用ROW_NUMBER()函数(必选)在Mysql表格显示中显示行号? mysql> select * from work;
+------+-----------+
| name | work_days |
+------+-----------+
| john | 5 |
| jane | 7 |
| jane | 2 |
| john | 3 |
+------+-----------+
4 rows in set (0.01 sec) 不使用ROW_NUMBER(): mysql> SELECT nam
我正在尝试优化对我的数据库的查询。我有以下查询:
select date, (
select count(user_id)
from myTable
where logdate = date
) as value
from myTable;
据我所见,第二个值是有效计算的。但是,在MySQL中优化这类查询有什么常见的做法吗?
在选择数据时,我可以通过运行以下命令来显示使用GROUP BY对多少行进行分组:
SELECT id, created, COUNT(id) `count` FROM table
GROUP BY id
LIMIT 0,30
count字段很容易输出受GROUP BY影响的行数。在MySQL中,是否可以自动不包括只具有count值为1的任何行?
在MySQL中,我有一个表,表中有一列满是正整数,我想过滤掉所有的奇数。似乎在MySQL文档中没有任何内容。我尝试了以下查询。
select kapsule.owner_name,
kapsule.owner_domain,
count(xform_action)
from kapsule, rec_xform
where rec_xform.g_conf_id=kapsule.g_conf_id
and (count(xform_action))%2=0
group by kapsule.owner_name;
我只想保留count(xf
在MYSQL中,我试图理解聚合函数,并尝试northwind模式中的一些示例。
表雇员具有以下描述。
+-----------------+-------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-----------------+-------------+------+-----+---------+----------------+
| id
当我的SQL查询在查询中有一个count函数时,它不想显示DBGRID中的数据,并且我得到了一个"MySqlException was unhandled“错误。一旦我删除了count函数,它就会顺利地运行,并在DB网格上显示数据。
代码如下:
Dim cmd As New MySqlCommand("SELECT COUNT(a.client_id), a.CLIENT_ID,b.c_name, b.C_surname FROM tblinv_info a JOIN tblclientinfo b ON a.CLIENT_ID = b.CLIENT_ID WHERE ext
我不知道该怎么说。
我有一个问题:
SELECT * , (
CASE
WHEN t.video_id IS NOT NULL
THEN pv.status
ELSE 4
END
) AS video_status
FROM `battles` `t`
LEFT JOIN process_videos pv ON ( pv.video_id = t.video_id )
WHERE title IS NOT NULL
AND cat_id IS NOT NULL
AND is_deleted =0
AND is_hidden =0
AND battle_type =
我使用w3s作为我在中的例子
SELECT Shippers.ShipperName,COUNT(Orders.OrderID) AS NumberOfOrders,
Orders.OrderDate
FROM Orders
LEFT JOIN Shippers
ON Orders.ShipperID=Shippers.ShipperID
GROUP BY ShipperName;
我很困惑,为什么上面的声明没有抛出一个错误。当我们通过所有的MySQL聚合时,MySQL如何知道要使用哪个OrderID
我一直试图在php上这样做,在mysql中读取一个db表,但我不能理解它的错误是什么。有人能帮帮我吗?包含数字的列形式的表(此数字表示课程:P)
SELECT *, MAX(COUNT(mi_curso)) maximo
FROM producto
GROUP BY mi_curso
这是显示的错误:
consulta SQL:
SELECT *, MAX(COUNT(mi_curso)) maximo
FROM producto
GROUP BY mi_curso LIMIT 0, 25
MySQL ha dicho: Documentación
#1111 - Invalid use
我有一个MySQL表,列名为"level“,如下所示。
| level
-----------
| High
| High
| Medium
| Low
| Low
| Medium
我将如何计算每个值发生的次数,从MS图(饼形图)控制数据源的一个查询中输出一个如下所示的表。
level | count
---------------
High | 1
Medium | 4
Low | 2
我正在尝试获取数据库中每天不同用户的计数。我的数据在一个本地的mysql数据库中,这个分区的代码没有给出我需要的数量。
select date(created) as created_at,
count(distinct user_id) over (PARTITION by date(created)) as ytd_count
from testdb.request_log;
SQL Workbench给我一个语法错误(P.
请帮帮忙?
我不是MySql方面的专家,我想做的是,创建一个查询将按月和年份返回正在运行的总计:
SELECT DISTINCT
date_format(t.created_at, "%M") AS month,
date_format(t.created_at, "%Y") AS year,
SUM(COUNT(*)) over (order by MONTH(created_at) ) as cumulative
FROM team t
GROUP BY YEAR(created_at), MONTH(created_at)
ORDER BY
可能重复:
简短但很简单:在MySQL中,SELECT COUNT(fld) AS count FROM tbl会比SELECT COUNT(*) AS count FROM tbl更快吗?据我所知,*是MySQL中的“所有”选择器。
COUNT(*)是否选择所有行来计算计数,从而使类似于SELECT(id)的查询更便宜?还是这真的不重要?
在更新到MySQL 5.7.11之后,我们得到了一些与sql_mode相关的错误,包括only_full_group_by。
研究表明,我们可以将其关闭,但最好知道如何使用结构合理的SQL语句来实现预期目标。
错误:
#1140 -在没有GROUP BY的聚合查询中,选择列表的表达式#1包含非聚合列‘tbllideshow.slideImage’;这与sql_mode=only_full_group_by不兼容
查询:
SELECT
tblslideshow.slideImage,
COUNT(tblslideshow.slideID) AS countVal
FROM
t
我想在running total中实现Impala示例,如下所示:
DATE | DAY | COUNT | Total
2014-11-12 | 1 | 12 | 12
2014-11-13 | 2 | 32 | 44
2014-11-14 | 3 | 50 | 94
To solve this problem using Impala, we might need temp variable like in MySql, which Impala does not suppo
我有以下SQL语句/ PHP记录集;
$sql_result= mysql_query("SELECT * FROM reports GROUP BY post DESC", $db);
while($rs = mysql_fetch_array($sql_result)) {
echo "post $rs[post] has $rs[num] reports<br>";
}
num字段不存在,但我希望它显示该组中有多少。我假设它在SQL中使用了COUNT,但不确定它在哪里。
有什么建议吗?
我有一些MySQL代码,如下所示:
SELECT
visitor AS team,
COUNT(*) AS rg,
SUM(vscore>hscore) AS rw,
SUM(vscore<hscore) AS rl
FROM `gamelog` WHERE status='Final'
AND date(start_et) BETWEEN %s AND %s GROUP BY visitor
我正在尝试将其转换为该查询的Django版本,而不进行多个查询。这个是可能的吗?我学习了如何做Sum()和Count(),但当我想要比较两个字段时,它似乎不