我有一个用于更新用户数据的表单。它发布到这个页面:(我已经删掉了与这个问题无关的内容)$qry="SELECT * FROM users WHERE userlogin = '$login' AND user_passwrd = sha1(CONCAT('$password', stamp))";
$result=<em
mysql_query("UPDATE users SET friends = CONCAT(friends,"$friend_id") WHERE username = '$user_logged_in'") or die mysql_error());mysql_query("UPDATE users SET friends = friends +" . ", " .
重要事项:这仅适用于续订版本<3mysql> SET FOREIGN_KEY_CHECKS = 0; truncate table myTable; SET FOREIGN_KEY_CHECKS =Error: ER_PARSE_ERROR: You have an error in your SQL syntax; check the