我有以下问题:-
Select
PUB.oa_inthed.adcode As Address_Code,
PUB.oa_intnom."due-date" As Commitment_Due_Date,
PUB.oa_inthed.company As Company,
PUB.oa_intnom.costcentre As Cost_Code,
PUB.oa_inthed.currency As Currency,
PUB.oa_inthed.description As Description,
PUB.oa_inthed.docdate As
我有以下XML: <oa:Parties>
<ow-o:SupplierParty>
<oa:PartyId>
<oa:Id>1</oa:Id>
</oa:PartyId>
</ow-o:SupplierParty>
<ow-o:CustomerParty>
<oa:PartyId>
<oa:Id>123-123</oa:Id> // I NEED THIS
</oa:PartyId>
在SSMS 2012中,我将看到在MS中创建的一个大视图。当我将视图脚本到查询窗口时,FROM子句如下所示:
FROM dbo.oa_projecttask_type RIGHT OUTER JOIN
dbo.oa_project_task RIGHT OUTER JOIN
dbo.[Functional Area] RIGHT OUTER JOIN
dbo.oa_category ON dbo.[Functional Area].[Product Code] = dbo.oa_category.name RIGHT OUTER JOIN
dbo
我想搜索一个只包含某些单词但不包含其他任何内容的字符串变量。
数据如下所示:
Osteoarthritis (OA)
OA (Osteoarthritis)
OA Knee
Osteoarthritis Knee
OA + hands
Osteoarthritis, hands
OA , hip
OA
Knee OA
我可以通过使用以下命令在一个输出中获得带膝的OA/Osteo
where prxmatch("m/osteoar|oa /oi", lowcase(diagnosis)) and prxmatch("/knee/", lowcase(diagnos
下面是我的SQL:
SELECT F9_OA008_DT||'|',
DED2(PX_OA008_PAN,'a')||'|',
F9_OA008_MCC||'|',
FX_OA008_MERC_NAME||FX_OA008_MERC_FILLER1||FX_OA008_MERC_CTY||FX_OA008_MERC_FILLER2||FX_OA008_MERC_ST_CNTRY||'|',
F9_OA008_AMT_REQ
FROM OA008
WHERE F9_OA008_MCC=5542 AND F9_OA0
当我在gem文件中添加了omnisocial之后运行bundle install时,我得到了这样的信息,实际上我已经安装了oa-core gem的最新版本:
Bundler could not find compatible versions for gem "oa-core":
In Gemfile:
omnisocial depends on
oa-core (~> 0.1.2)
omniauth depends on
oa-core (0.2.6)
..。
gem install oa-core
Successful
,这是我的控制器,我在这里切换了一下
class ProductController extends Controller
public function __construct()
{
$this->middleware('auth:api');
}
public function getdata()
{
$products = Product::get();
return view('table', [
'products'=>$products
]);
}
这里我从数据库中
我正在构建一个嵌套对象(一个1到多的嵌套树).或者,每个节点在每个深度上都有一个到多个,来自一个cypher查询,根据这个查询,我将返回一个包含嵌套对象的值,另一个值只包含最后一个嵌套对象中的ID数组。这是两个结果列,一个包含整个树,另一个只包含is。
使用: Seraph queryRaw(),Neo4j 2.1.3
MATCH (oa:ObjectA)-[:has]->(ob:ObjectB)-[:has]->(oc:ObjectC)<-[:extends]-(thing:ObjectThing)
WHERE ob.year = 2012
WITH
我正在通过ODBC连接上的MS查询运行以下查询:
SELECT oa_cstexpbal_0.costcentre, oa_cstexpbal_0.expensecode, oa_cstexpbal_0.yearno,
oa_cstexpbal_0.baltype, oa_cstexpbal_0.openbal, oa_cstexpbal_0.periodbal
FROM OPENACC.PUB.oa_cstexpbal oa_cstexpbal_0
WHERE (oa_cstexpbal_0.yearno='2016') AND (oa_cstexpbal_0.baltype
我试图过滤一些报告结果(Google Javascript regex支持),只包含包含模式"OA“的行,"OA”不能是字符串中的最后一个字符。下面的regex解决了“字符串问题中的最后一个字符”,但没有将匹配限制在那些具有"OA“实例的行中。我是应该包括另一个或语句来捕获该语句,还是应该更新当前的正则表达式以说明这一点?
,例如文本(预期结果):
OA > OA //No Match
Paid Search > OA //No Match
Paid Search > (none) > Social //No Match
OA > Paid
我跟随着:,但仍然是
ErrorException Required @OA\Info()未找到我将@OA\Info()放在控制器类中,如下所示,
<?php
namespace App\Http\Controllers;
use Illuminate\Foundation\Auth\Access\AuthorizesRequests;
use Illuminate\Foundation\Bus\DispatchesJobs;
use Illuminate\Foundation\Validation\ValidatesRequests;
use Illuminate\Routing\
我正在制作一个geom_line图。我想在x轴上使用与创建geom_line时使用的数据不同的数据来使用geom_rug。有关如何执行此操作的详细信息,可在此处找到:Using different data in ggplot's geom_rug than I use in the rest of the plot 我想用facet_grid做同样的事情,但是不知道怎么做。 以下是我用于创建geom_line的数据 data <- structure(list(id = c("1", "2", "3", "4",
std::ostringstream oss;
boost::archive::text_oarchive oa(oss);
我将可变数量的内容添加到此oa中,如下所示
oa & int1;
oa &int2;
--------------------> insert number of matrices here
oa & matrix1;
..//do some processing
oa & matrix2;
...//do some more
....
oa & matri