我试图从函数返回输出,并在for循环中执行函数调用,并在同一个循环中打印输出。但这是行不通的:
pagination_urls = ["http://google.com"]
def oss(url):
data = url
return data
for url in pagination_urls:
oss(url)
spider = data
print spider
输出:
Traceback (most recent call last):
File "mongo.py", line 10, in &l
我已经尝试将图片上传到我自己的服务器(Firebase)。我设法通过这个事件上传到了我的服务器上。
'froalaEditor.image.beforeUpload' : function(e, editor, images) {
let uploadTask: firebase.storage.UploadTask;
var time = Date.now()
let storageRef = firebase.storage().ref();
let path = `this.uid/Article_img/${time}`;
因此,我有以下功能,将所有图片uris状态并上传到firebase存储,然后用上传图片时生成的firebase下载urls替换处于状态的uris:
uploadImages = async (userID) => {
//loop through every image
for (var index = 0; index < this.state.images.length; index++) {
//convert image uri to blob
const response = await fetch(this.state.image