我正在尝试获取多个城市的房产列表的总金额。下面的代码只适用于1个城市,但我需要它来添加超过1个城市的总和。
这是MYSQL php在网站上的输出。
SELECT sum(case when p.city = 'Denver' then 1 else 0 end) ''
FROM __property AS p
LEFT JOIN __property_propmid as pm on pm.prop_id = p.id
LEFT JOIN __property_categories AS c on c.id = pm.cat_id
WHERE p.stype =
我有一个查询返回我的数据库表中所有"total“字段的总和。查询: public function findHoursTotal($user)
{
return $this->createQueryBuilder('h')
->where('h.user = :user')
->andWhere('h.date BETWEEN :start AND :end')
->select("SUM(h.total)")
->se
(语言PHP -这个问题适用于任何语言,特别是我正在使用PHP)例如,你有一个数字数组,如下所示:
$q = array( 1, 2, 3, 4, 5, ... ); // ... mean you can give more numbers
$i = 0;
$currentAverage = 0;
while ($i < count( $q )) {
$currentAverage = ($currentAverage + $q[$i]) / 2; // this is my try
$i++;
}
echo "The final average is: &
我有一组n×n点,浮点坐标的范围是0..n。如何在不使用暴力的情况下,为集合中的每个点分配一个网格点,以使“所需移动的总和”最小?
(最小化的总和=箭头长度的总和)
我想出的算法是:
for all remaining points in the set
calculate distances to each point's nearest available grid point
place point with smallest distance on its near grid point
remove that point from the set