我的代码出了什么问题?我一直收到这个错误:Warning: mysql_query(): supplied argument is not a valid MySQL-Link resource in functions.phpon line 4 error reading database
$result = mysql_query("SHOW TABLESLIKE '$gn'",$db)
我有这样的代码,它在目录中插入文件名到数据库中。include("db.php");
$directories = new RecursiveIteratorIterator>Warning: mysql_real_escape_string() [function.mysql-real-escape-string]: Access d