pieces - 腾讯云开发者社区

文章/答案/技术大牛

发布

HDU 4628 Pieces（状态压缩+记忆化搜索）

http://acm.hdu.edu.cn/showproblem.php?pid=4628 题意：给个字符窜，每步都可以删除一个字符窜，问最少用多少步可以删除...

7836 0

HOJ-2662Pieces Assignment(状态压缩，动态规划)

Pieces Assignment Source : zhouguyue Time limit : 1 sec Memory limit : 64 M Submitted : 415

5487 0

您找到你想要的搜索结果了吗？

是的

没有找到

图解LeetCode——1640. 能否连接形成数组（难度：简单）

另有一个由整数数组构成的数组 pieces，其中的整数也互不相同。请你以任意顺序连接 pieces 中的数组以形成 arr 。但是，不允许对每个数组 pieces[i] 中的整数重新排序。...arr = [49,18,16], pieces = [[16,18,49]] 【输出】false 【解释】即便数字相符，也不能重新排列 pieces[0] 2.3> 示例 3：【输入】arr = [...91,4,64,78], pieces = [[78],[4,64],[91]] 【输出】true 【解释】依次连接 [91]、[4,64] 和 [78] 提示： • 1 pieces.length...pieces[i][j] <= 100 • arr 中的整数互不相同 • pieces 中的整数互不相同（也就是说，如果将 pieces 扁平化成一维数组，数组中的所有整数互不相同...同时遍历arr和pieces中的元素，只要拿某个元素发现在index中存储的值为-1，或者pieces中数组元素内部排序不对，则直接返回false，不需要继续执行下去。

2313 1

【day09】LeetCode（力扣）每日一刷

另有一个由整数数组构成的数组 pieces，其中的整数也互不相同。请你以任意顺序连接 pieces 中的数组以形成 arr 。但是，不允许对每个数组 pieces[i]中的整数重新排序。...], pieces = [[16,18,49]] 输出：false 解释：即便数字相符，也不能重新排列 pieces[0] / 示例 3：输入：arr = [91,4,64,78], pieces...map来存放数组pieces中的数组首元素以及下标。...) { int len_arr = arr.length; //记录arr数组长度 int len_pieces = pieces.length;//记录pieces...(); //遍历pieces[][],将 pieces内每个数组的首元素，数组的下标>存入集合 for(int i = 0;i pieces;++i){

5242 0

LeetCode 1640. 能否连接形成数组（哈希）

另有一个由整数数组构成的数组 pieces，其中的整数也互不相同。请你以任意顺序连接 pieces 中的数组以形成 arr 。但是，不允许对每个数组 pieces[i] 中的整数重新排序。...示例 1：输入：arr = [85], pieces = [[85]] 输出：true 示例 2：输入：arr = [15,88], pieces = [[88],[15]] 输出：true 解释...：依次连接 [15] 和 [88] 示例 3：输入：arr = [49,18,16], pieces = [[16,18,49]] 输出：false 解释：即便数字相符，也不能重新排列 pieces...5：输入：arr = [1,3,5,7], pieces = [[2,4,6,8]] 输出：false 提示： 1 pieces.length <= arr.length <= 100 sum...(pieces[i].length) == arr.length 1 pieces[i].length <= arr.length 1 pieces[i][j] <= 100

3892 0

Python边学边用--BT客户端实现之

(pieces_num) + 1 if 20*pieces_num > len(pieces): return files...file_pieces = [] i = 0 pn = 0 while pn pieces_num:...# print (piece_index+pieces_num)*20, len(pieces),pieces_num,file_info['length'], self.get_piece_length...file_info['pieces'] = [] pn = 0 while pn pieces_num...: file_info['pieces'].append(pieces[piece_index*20:piece_index*20+20])

1.7K1 0

【CodeForces】632B - Alice, Bob, Two Teams（模拟）

The game involves splitting up game pieces into two teams....There are n pieces, and the i-th piece has a strength pi....The way to split up game pieces is split into several steps: First, Alice will split the pieces into...Alice will get all the pieces marked A and Bob will get all the pieces marked B....The strength of a player is then the sum of strengths of the pieces in the group.

3301 0

Educational Codeforces Round 44 (Rated for Div. 2)A. Chess Placing

Some cells of the board are occupied by the chess pieces....It is known that the total number of pieces equals to ? ....You cannot move pieces beyond the borders of the board....You also cannot move pieces to the cells that are already occupied....(1 ≤ pi ≤ n) — initial positions of the pieces.

5712 0

turf.js实现多边形分割

= []; if (_body.geometry.type === 'Polygon') { pieces.push(turf.polygon(_body.geometry.coordinates...)); } else { _body.geometry.coordinates.forEach(function (a) { pieces.push(turf.polygon(a)) });...处理点数据 for (p in pieces) { const piece = pieces[p]; for (let c in piece.geometry.coordinates...过滤掉重复点 for (p in pieces) { const coords = pieces[p].geometry.coordinates[0] pieces[p].geometry.coordinates...) a.properties.id += `-${index}` }); return turf.featureCollection(pieces); }

2.9K4 0

Python高能小技巧：用海象操作符减少重复代码

pieces = 0的赋值语句移动到else块中。...count = fresh_fruit.get('banana', 0) if count >= 2: pieces = slice_bananas(count) else: pieces...，因为if与else这两个分支都给pieces变量定义了初始值。...pieces = 0 if (count := fresh_fruit.get('banana', 0)) >= 2: pieces = slice_bananas(count) try:...if (count := fresh_fruit.get('banana', 0)) >= 2: pieces = slice_bananas(count) else: pieces =

6872 0

原来VSCode里藏了腾讯文档400行代码？鹅厂源码公开

_deserializeValue(pieces[1], strict) ); } if (serializedOne.indexOf("==") >= 0) { let pieces..._deserializeValue(pieces[1], strict) ); } if (serializedOne.indexOf("=~") >= 0) { let pieces...let pieces = serializedOne.split(" in "); return ContextKeyInExpr.create(pieces[0].trim(), pieces...("<="); return ContextKeySmallerEqualsExpr.create(pieces[0].trim(), pieces[1].trim()); } if ...(pieces[0].trim(), pieces[1].trim()); } if (/^\!

8053 0

腾讯AlloyTeam团队给 VSCode 贡献400+行核心代码增强其插件化能力

let pieces = serializedOne.split('=~'); return ContextKeyRegexExpr.create( pieces...0) { let pieces = serializedOne.split(' in '); return ContextKeyInExpr.create(pieces[...0].trim(), pieces[1].trim()); } if (serializedOne.indexOf('>=') >= 0) { const pieces...const pieces = serializedOne.split('>'); return ContextKeyGreaterExpr.create(pieces[0].trim()...pieces[1].trim() ); } if (serializedOne.indexOf('= 0) { const pieces =

1K2 0

Codeforces 842B Gleb And Pizza【几何，水】

When the courier delivered the pizza, he was very upset, because several pieces of sausage lay on the...Pieces of sausage are also circles....Gleb asks you to help determine the number of pieces of sausage caught on the crust....Next line contains one integer number n — the number of pieces of sausage (1 ≤ n ≤ 105)....Output Output the number of pieces of sausage that lay on the crust.

6806 0

【CodeForces】371C - Hamburgers（二分）

Polycarpus has nb pieces of bread, ns pieces of sausage and nc pieces of cheese in the kitchen....You can assume that Polycarpus cannot break or slice any of the pieces of bread, sausage or cheese....Besides, the shop has an unlimited number of pieces of each ingredient....The second line contains three integers nb, ns, nc (1 ≤ nb, ns, nc ≤ 100) — the number of the pieces

2361 0

模板方法模式

".format(item[0],item[1])) print("cut all vegetables in small pieces") def fry(self,):...输出结果为 ******************* aloomatar cook take aloo 1 Kg and cut into smaller pieces take matar 1/2 kg...and cut into smaller pieces cut all vegetables in small pieces wait 10 min Dish is ready to be served...******************* aloopyaz cook take pyaz 1/2 kg and cut into smaller pieces take aloo 1 Kg and cut...into smaller pieces cut all vegetables in small pieces fry for 5 minutes Dish is ready to be served

3323 0

【POJ】1753 - Flip Game（bfs，枚举）

37629 Accepted: 16368 Description Flip game is played on a rectangular 4x4 field with two-sided pieces...Each round you flip 3 to 5 pieces, thus changing the color of their upper side from black to white and...of the 16 pieces....lying their black side up and "w" denotes pieces lying their white side up....white side up or all pieces black side up.

2311 0

备忘录模式——实现象棋悔棋

chess; public ChessGame(Chess chess) { this.chess = chess; } public void show() { for(Pieces...Chess chess) { this.chess = chess; } } 备忘录 public class Chess { private LinkedListPieces...> list; public Chess(LinkedListPieces> lis) { list=new LinkedListPieces>(); Pieces p2; Iterator...Pieces> it=lis.iterator(); while(it.hasNext()) { p2=new Pieces((Pieces)it.next()); list.addLast...(p2); } } public LinkedListPieces> getList() { return list; } } 管理者 public class

3261 0

【HDU】1551 - Cable master（二分）

length of a cable piece that can be cut from the cables in the stock, to get the specified number of pieces...≤ N ≤ 10000) is the number of cables in the stock, and K (1 ≤ K ≤ 10000) is the number of requested pieces...Output For each testcase write to the output the maximal length (in meters) of the pieces that Cable...Master may cut from the cables in the stock to get the requested number of pieces....If it is not possible to cut the requested number of pieces each one being at least one centimeter long

2591 0

React | 借助Pragmatic Drag and Drop实现高性能拖拽

ref={ref} /> )}2.5 加入棋盘棋盘在初始化时，先设置棋子的位置，然后在renderSquares的TODO中添加棋子组件 // 初始化位置 const pieces...// 初始化位置const [pieces, setPieces] = useState([ { type: 'king', location: [3, 2] },...isEqualCoord(p.location, sourceLocation), ); const restOfPieces = pieces.filter(p => p...={pieces} location={squareCoord}> {piece && pieceLookup[piece.type...]); return ( {renderSquares(pieces)}

1.4K4 0

Python90-10 海象运算符 :=

pieces = 0 if (count := fresh_fruit.get('banana', 0)) >= 2: pieces = slice_bananas(count) try:...('banana', 0)) >= 2: pieces = slice_bananas(count) else: pieces = 0 try: smoothies = make_smoothies...(pieces) except OutOfBananas: out_of_stock() 刚接触Python的程序员发现缺乏switch/case语句(Pyhon3.10已经有了类似的功能match...count = fresh_fruit.get('banana', 0) if count >= 2: pieces = slice_bananas(count) to_enjoy =...= slice_bananas(count) to_enjoy = make_smoothies(pieces) elif (count := fresh_fruit.get('apple',

6954 0

点击加载更多

HDU 4628 Pieces（状态压缩+记忆化搜索）

HOJ-2662Pieces Assignment(状态压缩，动态规划)

图解LeetCode——1640. 能否连接形成数组（难度：简单）

【day09】LeetCode（力扣）每日一刷

LeetCode 1640. 能否连接形成数组（哈希）

Python边学边用--BT客户端实现之

【CodeForces】632B - Alice, Bob, Two Teams（模拟）

Educational Codeforces Round 44 (Rated for Div. 2)A. Chess Placing

turf.js实现多边形分割

Python高能小技巧：用海象操作符减少重复代码

原来VSCode里藏了腾讯文档400行代码？鹅厂源码公开

腾讯AlloyTeam团队给 VSCode 贡献400+行核心代码增强其插件化能力

Codeforces 842B Gleb And Pizza【几何，水】

【CodeForces】371C - Hamburgers（二分）

模板方法模式

【POJ】1753 - Flip Game（bfs，枚举）

备忘录模式——实现象棋悔棋

【HDU】1551 - Cable master（二分）

React | 借助Pragmatic Drag and Drop实现高性能拖拽

Python90-10 海象运算符 :=

相关资讯

热门标签

活动推荐

运营活动

社区

活动

圈层

关于

腾讯云开发者

热门产品

热门推荐

更多推荐