python - minimax算法通过用相同的符号填充每个空格来更新棋盘

import copy

def evaluate_board(board, player):
    # 这里可以根据具体的游戏规则评估棋盘状态
    # 返回一个分数，表示当前玩家的优势
    pass

def minimax(board, depth, is_maximizing_player):
    if depth == 0 or game_over(board):  # 游戏结束或达到最大深度
        return evaluate_board(board, is_maximizing_player)

    if is_maximizing_player:
        best_score = float('-inf')
        for move in get_possible_moves(board):
            new_board = copy.deepcopy(board)
            make_move(new_board, move, 'X')  # 假设'X'是最大化玩家的符号
            score = minimax(new_board, depth - 1, False)
            best_score = max(best_score, score)
        return best_score
    else:
        best_score = float('inf')
        for move in get_possible_moves(board):
            new_board = copy.deepcopy(board)
            make_move(new_board, move, 'O')  # 假设'O'是最小化玩家的符号
            score = minimax(new_board, depth - 1, True)
            best_score = min(best_score, score)
        return best_score

def find_best_move(board, depth):
    best_move = None
    best_score = float('-inf')
    for move in get_possible_moves(board):
        new_board = copy.deepcopy(board)
        make_move(new_board, move, 'X')  # 假设'X'是最大化玩家的符号
        score = minimax(new_board, depth - 1, False)
        if score > best_score:
            best_score = score
            best_move = move
    return best_move

def get_possible_moves(board):
    # 返回所有可能的移动
    moves = []
    for i in range(len(board)):
        for j in range(len(board[i])):
            if board[i][j] == ' ':  # 空格表示可以放置符号
                moves.append((i, j))
    return moves

def make_move(board, move, symbol):
    # 在棋盘上执行移动
    i, j = move
    board[i][j] = symbol

def game_over(board):
    # 检查游戏是否结束
    pass

# 示例棋盘
board = [
    ['X', ' ', 'O'],
    [' ', 'X', 'O'],
    ['O', ' ', 'X']
]

# 找到最佳移动
best_move = find_best_move(board, depth=3)
print("Best move:", best_move)