两个python解释器会话。第一个是来自CentOS上的python。第二个版本来自MacOSX10.7上内置的python。为什么第二个会话从\U转义序列中创建长度为2的字符串,并随后出错?
$ python
Python 2.6.6 (r266:84292, Dec 7 2011, 20:48:22)
[GCC 4.4.6 20110731 (Red Hat 4.4.6-3)] on linux2
Type "help", "copyright", "credits" or "license" for more infor
我目前正在尝试“集体智能编程”这本书中的一些代码,我遇到了这个由pydelicious.py引起的错误。有人能告诉我如何调试这样的问题吗?
Python代码:
def initializeUserDict(tag, count = 5):
user_dict = {}
#get the top count' popular posts
for p1 in get_popular(tag = tag)[0:count]:
#find all users who posted this
for p2 in get_urlposts(p1['href']):
我想在Python2.7中打印字符串的unicode版本。它在Python 3中运行得很好。但是使用python2.7,我得到了以下错误:
x="strings are now utf-8 \u03BCnico\u0394é!"
Python 3:
print('Python', python_version())
print(x)
Python 3.4.1
strings are now utf-8 μnicoΔé!
Python2.7
>>> x='strings are now utf-8 \u03BCnico\u0394é!&
使用正式安装程序,macOS 11.6/Xcode 13上的新诗安装失败:
u@s-MacBook-Pro ~ % curl -sSL https://install.python-poetry.org | python3 -
Retrieving Poetry metadata
# Welcome to Poetry!
This will download and install the latest version of Poetry,
a dependency and package manager for Python.
It will add the `poetry` comm
我有下一个正则表达式来查找文本上的表情符号:
re.compile(u'([\U00002600-\U000027BF])|([\U0001F300-\U0001F64F])|([\U0001F680-\U0001F6FF])')
它在Python3中工作得很好,但在Python2.7中我得到了这样的结果:
sre_constants.error: bad character range
我如何修复它以同时支持Python2.7和Python3?
我正在尝试R中python中的简单白化函数
Python
def svd_whiten(X):
U, s, Vt = np.linalg.svd(X, full_matrices=False)
#print(U)
#print(Vt)
# U and Vt are the singular matrices, and s contains the singular values.
# Since the rows of both U and Vt are orthonormal vectors, then U * Vt
# will be wh
我正在尝试通过pip安装元音:
sudo pip install vowpalwabbit
The directory '/home/user/.cache/pip/http' or its parent directory is not owned by the current user and the cache has been disabled. Please check the permissions and owner of that directory. If executing pip with sudo, you may want sudo's -H
我在Python中遇到了一个奇怪的地方,我不明白:
>>> x = 1
>>> L = [1, 2]
>>> u = True
>>> x in L == u
False
>>> (x in L) == u
True
>>> x in (L == u)
TypeError: argument of type 'bool' is not iterable.
有人能解释一下Python是如何处理x in L == u和(x in l) == u的吗?
谢谢。
Python版本
当我试图升级这个系统的时候,我会犯一些错误,我对debian很陌生,并且一直在尝试安装一些依赖于python的模块。但我似乎无法安装其中任何一个,甚至其他应用程序也无法升级或更新。
Reading package lists... Done
Building dependency tree
Reading state information... Done
Calculating upgrade... Done
The following packages will be upgraded:
bind9-host dnsutils google-chrome-stable h
下面是一个简单的测试。repr似乎工作得很好。然而,在Python2.6和2.7中,len和x for x in似乎没有正确地划分unicode文本:
In [1]: u""
Out[1]: u'\U0002f920\U0002f921'
In [2]: [x for x in u""]
Out[2]: [u'\ud87e', u'\udd20', u'\ud87e', u'\udd21']
好消息是Python3.3做了正确的事情,™。
Python2.x系列还有希望吗?