python:如何从一天内的时间步长获取最大聚合值？

import datetime

time_steps = [datetime.time(0, 0), datetime.time(1, 0), datetime.time(2, 0), ...]

aggregated_values = {}

for time_step in time_steps:
    max_value = max([data for data in data_list if data.time() <= time_step])
    aggregated_values[time_step] = max_value

for time_step, max_value in aggregated_values.items():
    print(f"时间步长 {time_step} 的最大聚合值为 {max_value}")