我想使用pandas从csv数据中加载姿势和运动。但是当我想要加载数据时,我总是得到这样的错误消息:
C:\Python\Python37\lib\site-packages\sklearn\linear_model\_logistic.py:765: ConvergenceWarning: lbfgs failed to converge (status=1):
STOP: TOTAL NO. of ITERATIONS REACHED LIMIT.
Increase the number of iterations (max_iter) or scale the data as show
有没有办法在Python中找到r置信区间?
在R中,我可以这样做:
cor.test(m, h)
Pearson's product-moment correlation
data: m and h
t = 0.8974, df = 4, p-value = 0.4202
alternative hypothesis: true correlation is not equal to 0
95 percent confidence interval:
-0.6022868 0.9164582
sample estimates:
cor
0.4093729
我试图计算python中高斯的积分,如下所示:
from math import exp
from scipy import stats, integrate
import scipy.interpolate as interpolate
from numpy import cumsum, random, histogram, linspace, zeros, inf, pi,sqrt
import matplotlib.pyplot as plt
A = 1
mu = 0
sigma = 1
p = lambda x: A * exp(-(((x-mu)**2))/(2*(sigma**2
最近,我在Tardos和Kleinberg的“算法设计”第四章中读到了区间调度算法。为间隔调度问题提供的解决方案如下:
Sort the n intervals based on their finishing time and store in array F
A = [] #list of intervals
S = array with property that S[i] contains the finishing time of the ith interval
i = 0
For j = 0 to n-1
if S[j] >= F[i] #this interval
我想找出服从正态分布的样本的置信区间。
为了测试代码,我首先创建了一个示例,并尝试在Jupyter notebookpython内核中绘制一幅置信区间图
%matplotlib notebook
import pandas as pd
import numpy as np
import statsmodels.stats.api as sms
import matplotlib.pyplot as plt
s= np.random.normal(0,1,2000)
# s= range(10,14) <---this sample has the
我有一个GENDER=(1/0)收入SENIORITY=(1/0)的数据。我需要为SENIORITY=1进行一项按性别划分的收入测试。据我所知,HO=0的默认设置意味着性别之间没有区别,但我如何定义一个HO,来检查mu of will (gender=1)是否是=higher=而非mu of (gender=0)。
这是我的基本代码:
proc ttest data=l;
var INCOME;
class gender;
where SENIORITY=1;
run;
在Python中实现随机事件的最佳方法是什么?
例如:
变量a设置为1,概率为0.8,否则为2。
到目前为止,我已经这样做了如下:
import random
a = 0 #Initialize a to 0
prob = random.random() #ask Python for a random float between 0 and 1
if prob < 0.8:
a = 1
else:
a = 2
这类案件还有别的办法吗?
def mean_slope(f, a, b):
'''
Write a python function which returns the average slope of a function f within a range a and b.a < b
'''
print(mean_slope(some_func, 2, 8))
如何编写python函数,它返回函数f在a和b.a <b范围内的平均斜率
我正在使用RecordRTC并尝试每隔1分钟保存一次视频,但是为了保存视频,我必须调用stopRecording()。例如:
function postFiles() {
var blob = recorder.getBlob();
// getting unique identifier for the file name
var fileName = generateRandomString() + '.webm';
var file = new File([blob], fi