python，包含元组的列表，查找连续数字

def find_continuous_numbers(tuple_list):
    result = []
    for tuple in tuple_list:
        is_continuous = True
        for i in range(len(tuple)-1):
            if tuple[i+1] != tuple[i] + 1:
                is_continuous = False
                break
        if is_continuous:
            result.append(tuple)
    return result

tuple_list = [(1, 2, 3), (4, 5, 6), (7, 8, 9), (10, 11, 13)]
continuous_tuples = find_continuous_numbers(tuple_list)
print(continuous_tuples)