python-使用os.walk查找文件名中具有最高值的文件

import os

def get_highest_number(filename):
    base_name = os.path.basename(filename)  # 获取文件名
    numbers = [int(s) for s in base_name.split() if s.isdigit()]  # 提取文件名中的数字
    if numbers:
        return max(numbers)  # 返回最高值
    else:
        return 0  # 如果文件名中没有数字，则返回0

def find_highest_number_file(directory):
    highest_number = 0
    highest_file = None

    for root, dirs, files in os.walk(directory):
        for file in files:
            file_path = os.path.join(root, file)
            current_number = get_highest_number(file_path)
            if current_number > highest_number:
                highest_number = current_number
                highest_file = file_path

    return highest_file

# 使用示例
directory = "/path/to/directory"  # 替换为实际目录
highest_file = find_highest_number_file(directory)

if highest_file:
    print("具有最高值的文件是：", highest_file)
else:
    print("目录中没有包含数字的文件名。")