一个大兄弟本地用了 PHP 7.1 进行开发，而我本地是 PHP 7.0, 于是悲剧发生了。
2021-11-13：至少有 K 个重复字符的最长子串。给你一个字符串 s 和一个整数 k ，请你找出 s 中的最长子串， 要求该子串中的每一字符出现次数都不少于 k 。返回这一子串的长度。提示：1 <= s.length <= 10的4次方，s 仅由小写英文字母组成，1 <= k <= 10的5次方。力扣395。
发布者：全栈程序员栈长，转载请注明出处：https://javaforall.cn/137778.html原文链接：https://javaforall.cn
前段时间，团队开放了组件库演示环境，由于存在一些小伙伴在外地办公（只能外网或者 vpn 到内网）。所以，为了安全考虑，设想是否可以通过 Nginx 做一些访问限制呢？当然，答案是肯定的。
1. Golang的特点和发起目的 Golang的特点以及要解决的问题概括起来就是三点: 1. concurrent : 多核 解决方式-> 语言层级并发, goroutine 2. garbage-collected language : c/c++的不足 3. fast compilation : c/c++等的不足, 依赖简单，类型系统简单，非传统OO。开发更简单快捷。 这种简单设计的特点很容易让人和C++对比，对比C++就是砍了90%特性，减少90%的麻烦。更好的对比可能是C，better
Golang的特点以及要解决的问题概括起来就是三点: 1. concurrent : 多核 解决方式-> 语言层级并发, goroutine 2. garbage-collected language : c/c++的不足 3. fast compilation : c/c++等的不足, 依赖简单，类型系统简单，非传统OO。开发更简单快捷。 这种简单设计的特点很容易让人和C++对比，对比C++就是砍了90%特性，减少90%的麻烦。更好的对比可能是C，better c with goroutine and garbage-collection。
开发平台是Mac，需要用到Python的图像处理库PIL，下面记录了安装过程以及出现的问题。
在 Linux 上使用 pip 安装 tensorflow 的时候，提示找不到匹配的包 $ pip install tensorflow Downloading/unpacking tensorflow Could not find any downloads that satisfy the requirement tensorflow Cleaning up... No distributions at all found for tensorflow Storing complete log in
mysqladmin:无法更改密码；错误：“您的密码不符合当前策略要求” Warning: Since password will be sent to server in plain text, use ssl connection to ensure password safety. mysqladmin: unable to change password; error: ‘Your password does not satisfy the current policy requirements’
1600 - Lucky Numbers 时间限制：2秒 内存限制：64兆 401 次提交 109 次通过 题目描述 Isun loves digit 4 and 8 very much. He thinks a number is lucky only if the number satisfy the following conditions: 1. The number only consists of digit 4 and 8. 2. The numbe
Composer是PHP中用来管理依赖（dependency）关系的工具。你可以在自己的项目中声明所依赖的外部工具库（libraries），Composer会帮你安装这些依赖的库文件。接下来通过本文给大家介绍Composer设置忽略版本匹配的方法，需要的朋友参考下吧
Once upon a time there was a greedy King who ordered his chief Architect to build a wall around the King’s castle. The King was so greedy, that he would not listen to his Architect’s proposals to build a beautiful brick wall with a perfect shape and nice tall towers. Instead, he ordered to build the wall around the whole castle using the least amount of stone and labor, but demanded that the wall should not come closer to the castle than a certain distance. If the King finds that the Architect has used more resources to build the wall than it was absolutely necessary to satisfy those requirements, then the Architect will loose his head. Moreover, he demanded Architect to introduce at once a plan of the wall listing the exact amount of resources that are needed to build the wall.
指令: log_not_foundon | off; 默认值: log_not_found on; 配置上下文: http, server, location
This question can be answered from a couple of perspectives: the hardware view and the Linux software view.
A. Lesha and array splitting time limit per test：2 seconds memory limit per test：256 megabytes input：standard input output：standard output One spring day on his way to university Lesha found an array A. Lesha likes to split arrays into several parts. This
我在这里分享一篇关于 MySQL 的可重复读介绍，讲得挺好的，可以解决一些疑惑，链接在下方引用处。
总言之，条件类型就是在类型中添加条件分支，以支持更加灵活的泛型，满足更多的使用场景。
E. Arrange Teams time limit per test:2 seconds memory limit per test:64 megabytes input:standard input output:standard output Syrian Collegiate Programming Contest (SCPC) is the qualified round for the Arab Collegiate Programming Contest. Each year SCPC or
Problem Description For hundreds of years Fermat’s Last Theorem, which stated simply that for n > 2 there exist no integers a, b, c > 1 such that a^n = b^n + c^n, has remained elusively unproven. (A recent proof is believed to be correct, though it is still undergoing scrutiny.) It is possible, however, to find integers greater than 1 that satisfy the “perfect cube” equation a^3 = b^3 + c^3 + d^3 (e.g. a quick calculation will show that the equation 12^3 = 6^3 + 8^3 + 10^3 is indeed true). This problem requires that you write a program to find all sets of numbers {a, b, c, d} which satisfy this equation for a <= 200.
在忘记MySQL密码的时候，会使用skip-grant-tables选项，下面记录一下在MySQL8.0环境中使用skip-grant-tables的情况。
上半年遇到了一些绑核相关的 bug，分析了其原因，但没有总结整理下来，现在又碰到了，补一下作业，同时也希望可以帮助大家快速从坑里爬出来。本篇会总结绑核相关的 bug，部分官网已修复，部分尚未修复，与 k8s 版本有关，感兴趣的可以对 k8s 进行一些考古，翻一翻从 1.8 到现在 CPU Manager 的发展过程，当然下面也会做简单介绍。
http://dev.mysql.com/doc/mysql-yum-repo-quick-guide/en/
最近在几个技术交流群经常看到大家讨论开发行业内卷，什么是内卷呢？一句话，大家越来越努力，越来越累，但是幸福感和收获并没有增加，甚至实际上是下降了。
Natasha is going to fly to Mars. She needs to build a rocket, which consists of several stages in some order. Each of the stages is defined by a lowercase Latin letter. This way, the rocket can be described by the string — concatenation of letters, which correspond to the stages.
在centos 7.4上yum安装了mysql 5.7后,发现mysql 5.7默认的root用户有了密码,而且设置为空密码时会受到安全限制,报错信息如下 Your password does not satisfy the current policy requirements 按照这个答案,用root登录mysql,运行 uninstall plugin validate_password; 则可以肆无忌惮的为root设置空密码
Nginx 介绍 Nginx (engine x) 是一个高性能的HTTP和反向代理服务器，也是一个IMAP/POP3/SMTP服务器。 Nginx是一款轻量级的Web 服务器/反向代理服务器及电子邮件（IMAP/POP3）代理服务器，并在一个BSD-like 协议下发行。其特点是占有内存少，并发能力强 OpenResty介绍 OpenResty 是一个基于 Nginx 与 Lua 的高性能 Web 平台，其内部集成了大量精良的 Lua 库、第三方模块以及大多数的依赖项。用于方便地搭建能够处理超高并发、扩展性极高的动态 Web 应用、Web 服务和动态网关
原文链接：http://intercax.com/2018/01/11/model-based-systems-engineering-autonomous-vehicles-part-1/
MySQL5.7为root用户随机生成了一个密码，打印在error_log中，关于error_log的位置，如果安装的是RPM包，则默认是 /var/log/mysqld.log 。 于是我们可以在mysqld.log中找到初始密码串：
执行 npm start,npm testing正常，执行npm build报错如下
说到http协议，其实大家都不陌生，我们日常上网，打开网页，使用的就是http协议，实现web浏览功能。
[!] Unable to satisfy the following requirements:
1 https://flyyufelix.github.io/2017/11/17/direct-future-prediction.html
选择在满足一些明确的客观标准时做得最好的预测变量的子集，例如具有最大R2值或最小MSE， Cp或AIC。
语法格式如下， 需要使用 [T Ttype] 指定约束条件， 例如 [T any] 不做任何约束, [T MyInterface] 满足 MyInterface 的约束
#概述 由于JVM中垃圾收集器的存在，使得Java程序员在开发过程中可以不用关心对象创建时的内存分配以及释放过程，当内存不足时，JVM会自动开启垃圾收集线程，进行垃圾对象的回收。 那么垃圾回收线程到底
Wall Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 40363 Accepted: 13754 Description
Problem Description Now given two kinds of coins A and B,which satisfy that GCD(A,B)=1.Here you can assume that there are enough coins for both kinds.Please calculate the maximal value that you cannot pay and the total number that you cannot pay.
概述 由于JVM中垃圾收集器的存在，使得Java程序员在开发过程中可以不用关心对象创建时的内存分配以及释放过程，当内存不足时，JVM会自动开启垃圾收集线程，进行垃圾对象的回收。 那么垃圾回收线程到
MiniZinc是一个用来描述整数和实数的优化约束和决策问题的语言，它允许用户以接近问题的数学公式的方式编写模型。
说明！！ 这个系统安装了compiz fusion(超炫界面)，gtweakui,startupmanager(系统管理工具),awn,cairo-dock(dock), install packages sudo aptitude install sun-java6-jdk eclipse stardict mozilla-thunderbird axel moto4lin mysql-server-5.0 tomcat5.5 gtweakui startupmanager build-essential rar zip avant-window-navigator-bzr awn-core-applets-bzr compiz-gnome compiz-fusion-plugins-extra compiz-fusion-plugins-main compizconfig-settings-manager libcompizconfig-backend-gconf emerald cairo-dock cairo-dock-plug-ins mplayer w32codecs mozilla-mplayer source.list # See http://help.ubuntu.com/community/UpgradeNotes for how to upgrade to # newer versions of the distribution. deb http://cn.archive.ubuntu.com/ubuntu/ gutsy main restricted deb-src http://cn.archive.ubuntu.com/ubuntu/ gutsy main restricted ## Major bug fix updates produced after the final release of the ## distribution. deb http://cn.archive.ubuntu.com/ubuntu/ gutsy-updates main restricted deb-src http://cn.archive.ubuntu.com/ubuntu/ gutsy-updates main restricted ## N.B. software from this repository is ENTIRELY UNSUPPORTED by the Ubuntu ## team, and may not be under a free licence. Please satisfy yourself as to ## your rights to use the software. Also, please note that software in ## universe WILL NOT receive any review or updates from the Ubuntu security ## team. deb http://cn.archive.ubuntu.com/ubuntu/ gutsy universe deb-src http://cn.archive.ubuntu.com/ubuntu/ gutsy universe deb http://cn.archive.ubuntu.com/ubuntu/ gutsy-updates universe deb-src http://cn.archive.ubuntu.com/ubuntu/ gutsy-updates universe ## N.B. software from this repository is ENTIRELY UNSUPPORTED by the Ubuntu ## team, and may not be under a free licence. Please satisfy yourself as to ## your rights to use the software. Also, please note that software in ## multiverse WILL NOT receive any review or updates from the Ubuntu ## security team. deb http://cn.archive.ubuntu.com/ubuntu/ gutsy multiverse deb-src http://cn.archive.ubuntu.com/ubuntu/ gutsy multiverse deb http://cn.a
Problem # Reverse a linked list from position m to n. Do it in-place and in one-pass. # # For example: # Given 1->2->3->4->5->NULL, m = 2 and n = 4, # # return 1->4->3->2->5->NULL. # # Note: # Given m, n satisfy the following condition: # 1 ≤ m ≤ n ≤ le
年底了，你的数据库是不是该巡检了？一般巡检都会关心密码安全问题，比如密码复杂度设置，是否有定期修改等。特别是进行等保评测时，评测机构会要求具备密码安全策略。其实 MySQL 系统本身可以设置密码复杂度及自动过期策略的，可能比较少用，大多数同学并未详细去了解。本篇文章我们一起来学习下如何设置数据库账号密码复杂度及自动过期策略。
Reverse a linked list from position m to n. Do it in-place and in one-pass.
Ubuntu base install
Reverse a linked list from position m to n. Do it in-place and in one-pass. For example: Given 1->2->3->4->5->NULL, m = 2 and n = 4, return 1->4->3->2->5->NULL. Note: Given m, n satisfy the following condition: 1 ≤ m ≤ n ≤ length of list. 将指定区间内的链表
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