$sql = "UPDATE Sales SET salequantity='$takeCount' JOIN Sales ON Inventory.saleIDUPDATE Sales INNER JOIN Sales ON Inventory.saleID=Sales.ID SET salequantity=2 where Sales.customerID=1 AND Inventory.productID=1;
从第一个注释运行查询,但也失败了。
$random_salt);
//if ($update_stmt = $mysqli->prepare("UPDATE{
if ($update_stmt = $mysqli->prepare("UPDATE members SET password = '".$password."', salt = &
我在MongoDB上有一个使用Mongoid的应用程序,一个更新正在悄悄地失败。# Are we getting a new attribute? Yes we are!p "attr first name = #{@attributes['first_name']}"
db.users.update({ "_id": &qu